Prime factors of 24x2
1 answer:
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the amount of gold present is - 9/10 of an ounce of gold
from this gold they have to split into groups of 1/6 ounce each
so we have to divide 9/10 ounce in to groups of 1/6
for this we have to divide 9/10 by 1/6
when dividing fractions we mutiply the first fraction by the reciprocal of the second fraction
reciprocal of 1/6 is - 6/1
so the number of groups that can be made is 5 whole groups with 0.4 ounce of gold remaining
the whole number of groups that can be made - 5