1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anvisha [2.4K]
3 years ago
15

Help help help math math

Mathematics
1 answer:
serg [7]3 years ago
5 0
Ok done. Thank to me :>

You might be interested in
You are pulling up an anchor while on a boat. You pull up the anchor at a rate of 0.5 feet per second. After 6 seconds, the anch
lys-0071 [83]

Answer:

the answer is 19

Step-by-step explanation:

8+6=14

14+5=19

4 0
3 years ago
In the Health ABC Study, 543 subjects owned a pet and 1977 subjects did not. Among the pet owners, there were 293 women; 975 of
True [87]

Answer:

The proportion of pet owners who were women is 0.540.

The proportion of non-pet owners who were women is 0.493.

Step-by-step explanation:

The data provided is summarized in the table below.

               Pet Owners      Non-Pet Owners    TOTAL

Men              250                       1002                1252

Women         293                        975                1268

TOTAL          543                       1977                2520

Denote the events as follows:

<em>W</em> = a subject is a women

<em>P</em> = a subject is a pet owner

The probability of an event, say E, is defined as the ration of the favorable outcomes of <em>E</em> to the the total number of outcomes of the experiment.

P (E) = n (E) ÷ N

Here,

n (E) = favorable outcome

N = total number of outcomes

(1)

The conditional probability of an event <em>B</em> given that another events <em>A</em> has already occurred is:

P (B | A) = n (A ∩ B) ÷ n (A)

Compute the probability of a pet owner being a women as follows:

P (W | P) = n (W ∩ P) ÷ n (P)

              = 975 ÷ 1977

              = 0.5396

              ≈ 0.540

Thus, the proportion of pet owners who were women is 0.540.

(2)

Compute the probability of a non-pet owner being a women as follows:

P (W | P') = n (W ∩ P') ÷ n (P')

              = 293 ÷ 543

              = 0.4932

              ≈ 0.493

Thus, the proportion of non-pet owners who were women is 0.493.

8 0
3 years ago
I need help!!!!!!!!!!!!!!!
jarptica [38.1K]

Answer:

5m = 3890

Step-by-step explanation:

6 0
3 years ago
Ajaaaaaaaaaaaaaaaaaaa<br> 28181x6
lilavasa [31]

Answer:

169086

Step-by-step explanation:

28181 x 6 = 169086

Use a calculator?

8 0
3 years ago
The price of a train ride is $12 it went up by 1/6 what is the new price<br><br><br> Please help
Serggg [28]
Answer::12/6 :))))))$
5 0
4 years ago
Other questions:
  • Which equation is equivalent to y-6=-12(x+4)
    6·2 answers
  • 65 in to the ratio 11:2​
    13·1 answer
  • Which statement is correct about a line and a point? Select one:
    5·1 answer
  • An item that was sellingfor 1,102 is redused to 806 .to the nearest whole what percent decrease
    11·1 answer
  • Solve 15 = 2^(x+1).
    11·1 answer
  • ANSWER GETS A BRAINLIEST
    15·2 answers
  • What value of r makes the following equation true​
    11·2 answers
  • What is 2+2 please answer this question right
    12·2 answers
  • The distance between City A and City B is 500 miles. A length of 1.8 feet represents this distance on a certain wall map. City C
    6·1 answer
  • What is the slope intercept form for x+3y=0
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!