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eduard
2 years ago
10

What is 23=5-2/3m ??????

Mathematics
1 answer:
Zielflug [23.3K]2 years ago
3 0

Answer:

Step-by-step explanation:

if it's

23 = 5 - (2/3)m

18 = (-2/3)m

m = 18(-3/2)

m = -27

if it's

23 = 5 - 2/(3m)

18 = -2/(3m)

18(3m) = -2

54m = - 2

m = -2/54

m = - 1/27

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The sum of 19.3 and a number is 30.4. Which equation can be used to solve the problem? n minus 19.3 = 30.4 19.3 + n = 30.4 19.3
Vlada [557]

Answer:

Below.

Step-by-step explanation:

19.3 + n  = 30.4

7 0
2 years ago
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How much would $500 invested at 8% interest compounded continuously be worth after 3 years? round your answer to the nearest cen
erik [133]
To solve this, you'll need the interest formula: <span> P(1 + rt). 

Then, plug in the numbers: 
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4 0
3 years ago
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-(-5 - 6x) = 4 (5x +3)
tatiyna

-(-5 - 6x) = 4 (5x +3)

Pretend that there is a -1 in front of the first bracket

-1(-5-6x)= 4(5x+3)

Mutiply the first bracket by -1

(-1)(-5)(-1)(-6x)= 5+6x

Mutiply the second bracket by 4

(4)(5x)(4)(3)= 20x+12

5+6x= 20x+12

move 20x to the other side

5+6x-20x= 20x-20x+12

5+6x-20x= 12

5-14x= 12

move 5 to the other side

sign changes from +5 to -5.

5-5-14x= 12-5

-14x=7

divide by -14

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x= -1/2

Answer: x= -1/2

6 0
3 years ago
Evaluate f(x)=x^2+1 for f(10)
marshall27 [118]
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4 0
3 years ago
Find the balance in the account after the given period.
Lapatulllka [165]

Answer:

balance after 4 years = $4502

Step-by-step explanation:

Formula to get the final amount when compounded annually is,

Final amount = \text{Principal amount}\times (1+\frac{r}{n})^{nt}

Here, r = rate of interest

n = number of compounding per year

t = Duration of investment

From the given question,

Final amount = 4000(1+\frac{0.03}{1})^{(1\times 4)}

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                      = 4502.0352

                      ≈ $4502

Therefore, balance after 4 years = $4502

8 0
3 years ago
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