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solniwko [45]
2 years ago
14

Please help quickly!! What is the radius, diameter and r2 of a circle with a 3cm area?

Mathematics
1 answer:
sdas [7]2 years ago
5 0

Answer:

area of a circle = pi*r^2

3 = pi*r^2

r^2 = 3/pi

r = √(3/pi)

diameter = 2*r = 2*√(3/pi)

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x = 18

Step-by-step explanation:

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3 years ago
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Complete the sequence.<br><br>37.25​, 35.5​, 33.75​, __, __.
Leviafan [203]

Answer:

37.25​, 35.5​, 33.75​, <u>32</u>, <u>30.25</u>.

Step-by-step explanation:

Subtract the first term from the second term:

35.5 - 37.25 = -1.75

Subtract the second term from the third term:

35.5 - 33.75 = -1.75

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To find each subsequent term, add the common difference to the current term.

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37.25​, 35.5​, 33.75​, <u>32</u>, <u>30.25</u>.

6 0
2 years ago
7 is a factor of <br> a 28<br> b 16<br> c 11<br> d 4
Blababa [14]

Answer:

a) 28

Step-by-step explanation:

4 0
2 years ago
A person's hourly pay rate, r, is found by dividing the total amount
marishachu [46]

Translating the words into formula, we have

r = \dfrac{p}{w}

In fact, we have that the pay rate is the total payment divided by the number of hours worked.

We can solve this formula for w in two steps: starting from the formula above, multiply both sides by w:

rw = p

And then divide both sides by r:

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4 0
3 years ago
preliminary sample of 100 labourers was selected from a population of 5000 labourers by simple random sampling. It was found tha
VladimirAG [237]

Answer:

n=\frac{0.4(1-0.4)}{(\frac{0.05}{1.96})^2}=368.79  

n=369

Step-by-step explanation:

1) Notation and definitions

X=40 number of the selected labourers opt for a new incentive scheme.

n=100 random sample taken

\hat p=\frac{40}{100}=0.4 estimated proportion of the selected labourers opt for a new incentive scheme.

p true population proportion of the selected labourers opt for a new incentive scheme.

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

2) Solution tot he problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.4(1-0.4)}{(\frac{0.05}{1.96})^2}=368.79  

And rounded up we have that n=369

8 0
3 years ago
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