All categories

3 years ago

Complete the sequence.37.25, 35.5, 33.75, , .

Mathematics

1 answer:

Leviafan [203]3 years ago

6 0

Answer:

37.25, 35.5, 33.75, 32, 30.25.

Step-by-step explanation:

Subtract the first term from the second term:

35.5 - 37.25 = -1.75

Subtract the second term from the third term:

35.5 - 33.75 = -1.75

The common difference is -1.75.

To find each subsequent term, add the common difference to the current term.

33.75 + (-1.75) = 32

32 + (-1.75) = 30.25

Answer:

37.25, 35.5, 33.75, 32, 30.25.

You might be interested in

Martin has collected 18 U.S. stamps and 12 international stamps. He wants to display them in identical groups of U.S. and intern

professor190 [17]

12 groups of two stamps

3 0

3 years ago

A point f(–3, 1) is translated along the vector ⟨5, –1⟩.what are the coordinates of the image f′ ?

jekas [21]

(2.0)

Hope this helped :)

7 0

2 years ago

Tracy McKinney is a disc jockey at radio station WMMM. Her annual salary is $52,750. What is her monthly salary?

attashe74 [19]

Okay, so since her annual salary is $52,750 (the amount she gets a year, all twelve months combined) you're trying to find how much she gets monthly. That would mean we would have to divide her annual salary by 12 to find her monthly salary.

$52,750 ÷ 12 = 4,395.8333333333333

And since that's a (bothersome) repeating decimal, we're going to have to round it. Once rounded, you would get $4,395.83. That is her monthly salary.

5 0

3 years ago

Ella and three friends run in a relay that is 14 miles long.Each person runs equal parts of the race.How many miles does each pe

sergeinik [125]

Each Person Runs: 3.5 miles.
14÷4= 3.5.

3 0

3 years ago

Read 2 more answers

1. A report from the Secretary of Health and Human Services stated that 70% of single-vehicle traffic fatalities that occur at n

Nuetrik [128]

Using the binomial distribution, it is found that there is a 0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

For each fatality, there are only two possible outcomes, either it involved an intoxicated driver, or it did not. The probability of a fatality involving an intoxicated driver is independent of any other fatality, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

70% of fatalities involve an intoxicated driver, hence $p = 0.7$ .

A sample of 15 fatalities is taken, hence $n = 15$ .

The probability is:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)$

Hence

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{15,10}.(0.7)^{10}.(0.3)^{5} = 0.2061$

$P(X = 11) = C_{15,11}.(0.7)^{11}.(0.3)^{4} = 0.2186$

$P(X = 12) = C_{15,12}.(0.7)^{12}.(0.3)^{3} = 0.1700$

$P(X = 13) = C_{15,13}.(0.7)^{13}.(0.3)^{2} = 0.0916$

$P(X = 14) = C_{15,14}.(0.7)^{14}.(0.3)^{1} = 0.0305$

$P(X = 15) = C_{15,15}.(0.7)^{15}.(0.3)^{0} = 0.0047$

Then:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.2061 + 0.2186 + 0.1700 + 0.0916 + 0.0305 + 0.0047 = 0.7215$

0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

A similar problem is given at brainly.com/question/24863377

5 0

3 years ago

Complete the sequence.37.25​, 35.5​, 33.75​, __, __.

Complete the sequence.37.25, 35.5, 33.75, , .