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kirza4 [7]
2 years ago
13

HELP!...................................................

Mathematics
1 answer:
DaniilM [7]2 years ago
7 0

Answer:

1.6 hrs remaining, or 3.12 km/h

Step-by-step explanation:

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The list shows the thickness of ice on the roads after a storm. On the line plot each x represents 1 measurement which line plot
dimulka [17.4K]

Answer:

Step-by-step explanation:

Ice sheets have one particularly special property. They allow us to go back in time and to sample accumulation, air temperature and air chemistry from another time[1]. Ice core records allow us to generate continuous reconstructions of past climate, going back at least 800,000 years[2].

Ice coring has been around since the 1950s. Ice cores have been drilled in ice sheets worldwide, but notably in Greenland[3] and Antarctica[4, 5]. High rates of snow accumulation provide excellent time resolution, and bubbles in the ice core preserve actual samples of the world’s ancient atmosphere[6].

4 0
2 years ago
2(c+1)=10 HELP PLSSSSSSSS
Nikolay [14]

Answer:

c=4  

Will venus1234 delete the c4?

Step-by-step explanation:

You simplify by distributive property

2c+2=10

Then you can use subtraction property of equality to subtract 2 from both sides to get  

2c=8

Then do division property of equality to get the unit rate of c.

You end up with

c=4

4

4

4

4

4

4

4

Hope this helps!

5 0
3 years ago
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4 0
3 years ago
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M∠PQS = 87°, and m∠SQR = 33°. what is m∠PQR.
defon
<span>Given:
∠PQS = 87°, and m∠SQR = 33°   find </span>m∠PQR .<span>


m∠PQR
= m</span>∠PQS + m∠SQR
= 87° + 33°
= 120°
7 0
3 years ago
What is the problem of this solving?!
nika2105 [10]
     This question can be solved primarily by L'Hospital Rule and the Product Rule.

y= \lim_{x \to 0}  \frac{x^2cos(x)-sin^2(x)}{x^4}
 
     I) Product Rule and L'Hospital Rule:

y= \lim_{x \to 0} \frac{[2xcos(x)-x^2sin(x)]-2sin(x)cos(x)}{4x^3}
 
     II) Product Rule and L'Hospital Rule:

y= \lim_{x \to 0} \frac{[-2xsin(x)+2cos(x)]-[2xsin(x)+x^2cos(x)]-[2cos^2(x)-2sin^2(x)]}{12x^2} \\ y= \lim_{x \to 0} \frac{2cos(x)-4xsin(x)-x^2cos(x)-2cos^2(x)+2sin^2(x)}{12x^2}
 
     III) Product Rule and L'Hospital Rule:

]y= \alpha + \beta \\ \\ \alpha =\lim_{x \to 0} \frac{-2sin(x)-[4sin(x)+4xcos(x)]-[2xcos(x)-x^2sin(x)]}{24x} \\ \beta = \lim_{x \to 0} \frac{4sin(x)cos(x)+4sin(x)cos(x)}{24x} \\  \\ y = \lim_{x \to 0} \frac{-6sin(x)-4xcos(x)-2xcos(x)+x^2sin(x)+8sin(x)cos(x)}{24x}
 
     IV) Product Rule and L'Hospital Rule:

y = \phi + \varphi \\  \\ \phi = \lim_{x \to 0}  \frac{-6cos(x)-[-4xsin(x)+4cos(x)]-[2cos(x)-2xsin(x)]}{24x}  \\ \varphi = \lim_{x \to 0}  \frac{[2xsin(x)+x^2cos(x)]+[8cos^2(x)-8sin(x)]}{24x}
 
     V) Using the Definition of Limit:

y= \frac{-6*1-4*1-2*1+8*1^2}{24}  \\ y= \frac{-4}{24}  \\ \boxed {y= \frac{-1}{6} }
3 0
3 years ago
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