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nikdorinn [45]
3 years ago
10

K=2LM + 2LN. Solve for L

Mathematics
2 answers:
AlladinOne [14]3 years ago
4 0
L = 0 bcause it cancels itself out
valentinak56 [21]3 years ago
3 0

Answer:

The value of the provide equation is L=\frac{K}{2M+2N}.

Step-by-step explanation:

Consider the provided equation.

K=2LM + 2LN

We need to solve the equation for L.

Take L common from right side.

K=L(2M + 2N)

Divide both the sides by 2M+2N.

\frac{K}{2M+2N}=\frac{L(2M + 2N)}{2M + 2N}

L=\frac{K}{2M+2N}

Hence, the value of the provide equation is L=\frac{K}{2M+2N}.

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24 : 8 = 3 : ?<br>7 : 35 = ? : 5<br>in detail please
Simora [160]
24 : 8 = 3 : 1 because 24 divided by 8 = 3 so
3 = 1

7 : 35 = 1 : 5 because 35 divided by 7 is 5 so
5 = 1
8 0
3 years ago
An IV infiltrates with 330 mL remaining in the bag. It was restarted at 1015 at a rate of 30 mL/hr. What is the IV completion ti
DochEvi [55]

Answer:

11 hours

Step-by-step explanation:

I came up with this answer by dividing the IV infiltrate in the bag by the rate. This gave the completion time.

Volume of IV infiltrate = 330ML

Rate at which it was running = 30 ML/hour

The IV completion time = volume/rate

= 330 ML/30 ML

= 11 hours

Therefore the IV completion time is 11 hours.

3 0
3 years ago
Marcus bought he used 50% on tickets on rides and 1/4 of the tickets on video games and the rest of the tickets in the batting c
GalinKa [24]

Answer:

Therefore Marcus is incorrect.

Step-by-step explanation:

Total ticket that Marcus bought= 100%.

Marcus used 50% of ticket on rides.

and he used  \frac{1}{4} of the tickets on the video games.

The percentage form of any number x is

=100\times x \%

The percentage form of \frac{1}{4} is

=\frac{1\times  100}{4} \%

=25%

Therefore rest tickets are

=Total ticket-( ticket used in rides + ticket used in video games)

=100% - (50%+25%)

=100% - 75%

=25%

Therefore he used 25% of tickets in batting cage.

But he said that Marcus said that he used 24% of ticket in batting cage.

Therefore Marcus is incorrect.

8 0
3 years ago
A 0.143-Henry Inductor is connected in series with a variable resistor to a 208-volt 400-cycle source. For what value of capacit
aleksandr82 [10.1K]

Answer:

A.)359.2, B.)2.5 uf

Step-by-step explanation:

E / I = R

208 / 1.04 = 200 ohms

2*pi*f*L = Xl

6.28*400*.143 = 359.2 ohm

1 / (2*pi*f*Xc) = c

1 /(6.28*400*159.2) = 2.5 uf

8 0
4 years ago
Can someone please help me do this
Viefleur [7K]

Answer:

Step-by-step explanation:

CD is Pole

∠CAD = 4°  {Alternate interior angles}

ΔCAD,

\dfrac{opposite \ side}{adjacent \ side}= tan 4\\\\ \dfrac{90}{AD}=tan \ 4\\\\ \dfrac{90}{AD} = 0.069\\\\90 = 0.069*AD\\\\ \dfrac{90}{0.069}=AD\\\\AD = 1304 \ ft

In ΔCDB,

∠B = 5° {Alternate interior angles}

Tan \ 5 = \dfrac{90}{BD}\\\\0.09* BD = 90\\\\BD =   \dfrac{90}{0.09}\\\\BD = 1000 \ ft

4 0
3 years ago
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