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3 years ago

Find the equation of the line that is parallel to x=5y-8 and pass through (6, -5) in slope intercept form

Mathematics

1 answer:

DochEvi [55]3 years ago

5 0

Answer:

y=1/5x-31/5 (or y=0.2x-6.2 in decimals)

Step-by-step explanation:

x=5y-8 (original equation)

x+8=5y (Addition Property of Equality)

1/5x+8/5=y (Division Property of Equality, slope of original equation is 1/5)

y-y1=m(x-x1) (point-slope formula)

y-(-5))=1/5(x-(6)) (plug in the slope that was found earlier and the point given in the question)

y+5=1/5(x-6)

y+5=1/5x-6/5 (Distributive Property of Multiplication) Note: 5 = 25/5

y=1/5x-31/5 (Subtraction Property of Equality, and there's your answer)

y=0.2x-6.2 (This is the same answer, but written with decimals)

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Step-by-step explanation:

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3 years ago

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3 years ago

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Write the equation of the line that passes through the points (-4,8) and (-2, -1).

IRINA_888 [86]

Answer:

y=-9/2x-10

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-1-8)/(-2-(-4))

m=-9/(-2+4)

m=-9/2

y-y1=m(x-x1)

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y-8=-9/2(x+4)

y=-9/2x-36/2+8

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5 0

3 years ago

Find the area of a circle circumscribing an equilateral triangle of side 15cm. Take pi = 3.14.

miskamm [114]

Answer:

236 cm²

Step-by-step explanation:

Height of an equilateral triangle (h) = √3 /2 (l)

l = side of the equilateral triangle.

h = √3 /2 (15)

In an equilateral triangle the orthocenter, centroid, circumcenter and incenter are in the same spot

The center of the circle is the centroid and height match with the median. The radius of the circumcircle is equal to two thirds the height.

Formula for the Radius of the circumcircle = 2/3 h

= 2/3 x √3 /2 (15)

= 5 √3 cm (=radius)

Area of the circle = πr^

= 3.14 x( 5 √3 ) ^

=3.14 x(25*3)

=3.14 x 75

=235.5

=236 cm²

8 0

3 years ago

If p is the midpoint of line xy, xp=11-6b and py=6-b, find xp

MariettaO [177]

Since p is the midpoint then xp and pay must equal each other
So, 11-6b=6-b
Solve for b
11-6b=6-b
-6 -6
5-6b=-b
+6b +6b
5=5b
b=1

xp=11-6(1)
xp=5

5 0

3 years ago

Find the equation of the line that is parallel to x=5y-8 and pass through (6, -5) in slope intercept form￼

Find the equation of the line that is parallel to x=5y-8 and pass through (6, -5) in slope intercept form