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2 years ago

Find the equation of the line that is parallel to x=5y-8 and pass through (6, -5) in slope intercept form

Mathematics

1 answer:

DochEvi [55]2 years ago

5 0

Answer:

y=1/5x-31/5 (or y=0.2x-6.2 in decimals)

Step-by-step explanation:

x=5y-8 (original equation)

x+8=5y (Addition Property of Equality)

1/5x+8/5=y (Division Property of Equality, slope of original equation is 1/5)

y-y1=m(x-x1) (point-slope formula)

y-(-5))=1/5(x-(6)) (plug in the slope that was found earlier and the point given in the question)

y+5=1/5(x-6)

y+5=1/5x-6/5 (Distributive Property of Multiplication) Note: 5 = 25/5

y=1/5x-31/5 (Subtraction Property of Equality, and there's your answer)

y=0.2x-6.2 (This is the same answer, but written with decimals)

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Morgarella [4.7K]

Answer:

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Step-by-step explanation:

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3 years ago

Find the equation of the line that is parallel to x=5y-8 and pass through (6, -5) in slope intercept form￼

Find the equation of the line that is parallel to x=5y-8 and pass through (6, -5) in slope intercept form