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tigry1 [53]
2 years ago
13

Find the equation of the line that is parallel to x=5y-8 and pass through (6, -5) in slope intercept form

Mathematics
1 answer:
DochEvi [55]2 years ago
5 0

Answer:

y=1/5x-31/5 (or y=0.2x-6.2 in decimals)

Step-by-step explanation:

x=5y-8     (original equation)

x+8=5y <u>(Addition Property of Equality)</u>

1/5x+8/5=y <u>(Division Property of Equality, </u><u>slope </u><u>of </u><u><em>original equation </em></u><u>is </u><u>1/5</u><u>)</u>

<u />

y-y1=m(x-x1)    <u>(point-slope formula)</u>

y-(-5))=1/5(x-(6)) <u>(plug in the slope that was found earlier and the point given in the question)</u>

y+5=1/5(x-6)

y+5=1/5x-6/5   (Distributive Property of Multiplication)   Note:  5 = 25/5

<u>y=1/5x-31/5</u> (Subtraction Property of Equality, and there's your answer)

<u>y=0.2x-6.2</u><em> </em>(This is the same answer, but written with decimals)

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\sf{\qquad\qquad\huge\underline{{\sf Answer}}}

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