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tigry1 [53]
3 years ago
13

Find the equation of the line that is parallel to x=5y-8 and pass through (6, -5) in slope intercept form

Mathematics
1 answer:
DochEvi [55]3 years ago
5 0

Answer:

y=1/5x-31/5 (or y=0.2x-6.2 in decimals)

Step-by-step explanation:

x=5y-8     (original equation)

x+8=5y <u>(Addition Property of Equality)</u>

1/5x+8/5=y <u>(Division Property of Equality, </u><u>slope </u><u>of </u><u><em>original equation </em></u><u>is </u><u>1/5</u><u>)</u>

<u />

y-y1=m(x-x1)    <u>(point-slope formula)</u>

y-(-5))=1/5(x-(6)) <u>(plug in the slope that was found earlier and the point given in the question)</u>

y+5=1/5(x-6)

y+5=1/5x-6/5   (Distributive Property of Multiplication)   Note:  5 = 25/5

<u>y=1/5x-31/5</u> (Subtraction Property of Equality, and there's your answer)

<u>y=0.2x-6.2</u><em> </em>(This is the same answer, but written with decimals)

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Answer:

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3 years ago
Let g(x)= -3x and h(x) x^2+3 Find (g°h)(0)
raketka [301]
<h3>Answer is   -9</h3>

=================================

Work Shown:

(g°h)(x) is the same as g(h(x))

So, (g°h)(0) = g(h(0))

Effectively h(x) is the input to g(x). Let's first find h(0)

h(x) = x^2+3

h(0) = 0^2+3

h(0) = 3

So g(h(x)) becomes g(h(0)) after we replace x with 0, then it updates to g(3) when we replace h(0) with 3.

Now let's find g(3)

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g(3) = -3*3

g(3) = -9

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alternatively, you can plug h(x) algebraically into the g(x) function

g(x) = -3x

g( h(x) ) = -3*( h(x) ) ... replace all x terms with h(x)

g( h(x) ) = -3*(x^2 + 3) ... replace h(x) on right side with x^2+3

g( h(x) ) = -3x^2 - 9

Next we can plug in x = 0

g( h(0) )  = -3(0)^2 - 9

g( h(0) ) = -9

we get the same result.

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3 years ago
Please help! (picture below)
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Answer:

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Step-by-step explanation:

hope that helps

6 0
3 years ago
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sp2606 [1]
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