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pogonyaev
2 years ago
14

Please help, I will give good rating and brainliest of possible!! Thank you!!!!!!!!

Mathematics
1 answer:
Leya [2.2K]2 years ago
3 0

Answer:

g(x)=x+8

Step-by-step explanation:

Translating a function up is very simple, all you need to do here is add 8.

If you want to think of it logically,

f(x)=x

the whole right side of the function here can be our output. If x is 8, then the output, or height, is also 8. if you wanted to translate that up to 10, you'd simply need to add 2 to it, meaning x+2. Then, at any given point on the function, it'd be 2 higher than it would be otherwise.

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Factor these expressions into an equivalent form.
Marrrta [24]
(c+8)(c-8)

3(2y+5)(2y-5)

There are no like terms so it's still ab^2-b
7 0
3 years ago
Read 2 more answers
What do you mean by mean (average)?collect the age of 8friends and calculate their average ages. ​
Arada [10]

Answer:

its basically the average

Step-by-step explanation:

To find it,add up all the numbers and then the answer that you get,you divide it by the amount of numbers you added up...

Hopefully this helped

7 0
3 years ago
Factor out completly: 6x^2y − 3xy − 24xy^2 + 12y^2
Crank
<h3>I'll teach you how to factor 6x^2y − 3xy − 24xy^2 + 12y^2</h3>

---------------------------------------------------------------------

6x^2y − 3xy − 24xy^2 + 12y^2

Apply exponent rule:

6x^2y-3xy-24xyy+12yy

Rewrite 12 as 4*3

Rewrite -24 as 8*3

Rewrite 6 as 2*3

2*3x^2y-3xy+8*3xyy+4*3yy

Factor out common term 3y:

3y(2x^2-x-8xy+4y)

Factor 2x^2-x-8xy+4y:

3y(2x-1)(x-4y)

Your Answer Is 3y(2x-1)(x-4y)

plz mark me as brainliest if this helped :)

8 0
3 years ago
If j and k are nonzero integers, which pair of points must lie in the same quadrant?
Marizza181 [45]
<h3>Answer:  Choice D.   (3j, 3k)  and (3/j, 3/k)</h3>

The slash indicates a fraction.

=============================================

Proof:

We'll need to consider 4 different cases.

-----------------------

Case (1): j > 0 and k > 0

If j > 0, then 3j > 0 and 3/j > 0

If k > 0, then 3k > 0 and 3/k > 0

The two points (3j, 3k) and (3/j, 3/k) are both in quadrant 1.

-----------------------

Case (2): j > 0 and k < 0

If j > 0, then 3j > 0 and 3/j > 0

If k < 0, then 3k < 0 and 3/k < 0

Points (3j, 3k) and (3/j, 3/k) are both in quadrant 4.

------------------------

Case (3): j < 0 and k > 0

If j < 0, then 3j < 0 and 3/j < 0

If k > 0, then 3k > 0 and 3/k > 0

Points (3j, 3k) and (3/j, 3/k) are in quadrant 3.

------------------------

Case (4): j < 0 and k < 0

If j < 0, then 3j < 0 and 3/j < 0

If k < 0, then 3k < 0 and 3/k < 0

Points (3j, 3k) and (3/j, 3/k) are in quadrant 4.

------------------------

For nonzero integers j and k, we've shown that Points (3j, 3k) and (3/j, 3/k) are in the same quadrant. This concludes the proof.

8 0
2 years ago
Read 2 more answers
-)) Aiden ordered a set of beads. He received 150 beads in all. 24 of the beads were brown. What
vesna_86 [32]

Answer:

16 %

Step-by-step explanation:

(24/150) . 100 = 16

5 0
2 years ago
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