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2 years ago

Find the sum 52,679 + 3,596

Mathematics

1 answer:

mojhsa [17]2 years ago

6 0

Answer:

56,275

Step-by-step explanation:

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What is the smallest solution to this equation?

Lapatulllka [165]

Answer:

x = - 6

Step-by-step explanation:

Given

$\frac{2}{3}$ x² = 24 ( multiply both sides by 3 )

2x² = 72 ( divide both sides by 2 )

x² = 36 ( take the square root of both sides )

x = ± $\sqrt{36}$ ← note plus or minus

x = ± 6

solutions are x = - 6, x = + 6

The smallest solution is x = - 6

8 0

3 years ago

What is the answer to number five?

VARVARA [1.3K]

Paid same amount is important.

5 hours each one, and 4 babysitters
5*4 is 20

And if there's 170 dollars she paid in total, then each babysitter earned 170/20 per hour, which is 8.5 dollars per hour

3 0

3 years ago

Steven paid 15% down on a car. His down payment was $2,100. How much does he still owe on the car?

My name is Ann [436]

Answer:

315

Step-by-step explanation:

because 15% of 2,100 is 315

3 0

3 years ago

The expected number of typographical errors on a page of a certain magazine is .2. What is the probability that an article of 10

Pavel [41]

Answer:

a) The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

Step-by-step explanation:

Given : The expected number of typographical errors on a page of a certain magazine is 0.2.

To find : What is the probability that an article of 10 pages contains

(a) 0 and (b) 2 or more typographical errors?

Solution :

Applying Poisson distribution,

$N\sim Pois(0.2)$

$P(N=r)=\frac{e^{-np}(np)^r}{r!}$

where, n is the number of words in a page

and p is the probability of every word with typographical errors.

Here, n=10 and E(N)=np=0.2

a) The probability that an article of 10 pages contains 0 typographical errors.

Substitute r=0 in formula,

$P(N=0)=\frac{e^{-0.2}(0.2)^0}{0!}$

$P(N=0)=\frac{e^{-0.2}}{1}$

$P(N=0)=e^{-0.2}$

$P(N=0)=0.8187$

The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors.

Substitute $r\geq 2$ in formula,

$P(N\geq 2)=1-P(N$

$P(N\geq 2)=1-[P(N=0)+P(N=1)]$

$P(N\geq 2)=1-[\frac{e^{-0.2}(0.2)^0}{0!}+\frac{e^{-0.2}(0.2)^1}{1!}]$

$P(N\geq 2)=1-[e^{-0.2}+e^{-0.2}(0.2)]$

$P(N\geq 2)=1-[0.8187+0.1637]$

$P(N\geq 2)=1-0.9825$

$P(N\geq 2)=0.0175$

The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

6 0

3 years ago

Answer Question number 5 <br><br>Plzzzz

Softa [21]

Step-by-step explanation:

Consider x⅓ =a

then the following expression can be written as

a²+a-2

a²+2a-a-2

a(a+2)-1(a+2)

(a+2)(a-1)

a= -2 or, a= 1

Putting the value of a

x⅓ = -2 and, x⅓ =1

6 0

3 years ago

Read 2 more answers