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1 year ago

Whats 4x5x6x32x4x4x4x4

Mathematics

1 answer:

adoni [48]1 year ago

5 0

Answer:

983,040

Step-by-step explanation:

4×5=20

6×32=192

4×4=16

20×192×16×16

=983,040

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What is the solution to the equation below? 1.5 (2x+ 5) +2.5 = 1.5 (-2x + 7)= 0.5

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2 years ago

Explain the process for finding the product of two integers

mafiozo [28]

Rule 1: The product of a positive integer and a negative integer is a negative integer. Rule 2: The product of two negative integers or two positive integers is a positive integer

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3 years ago

Solve the systems of equations by substitution 3/8x + 1/3y = 17/24 X + 7y = 8

Sedaia [141]

Answer:

If your solving for y...

The answer would be: y = -9/8x + 17/8 I believe.

For the second one... it would be : y = -1/7x + 8/7

Step-by-step explanation:

8 0

2 years ago

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Hi, can someone please help, and possibly explain the answer please.

mr_godi [17]

Answer:

$x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}$

Step-by-step explanation:

Quadratic formula: $x=\frac{-b\±\sqrt{b^2-4ac} }{2a}$ when the equation is $0=ax^2+bx+c$

The given equation is $1=-2x+3x^2+1$ . Let's first arrange this so its format looks like $y=ax^2+bx+c$ :

$1=-2x+3x^2+1$

$1=3x^2-2x+1$

Subtract 1 from both sides of the equation

$1-1=3x^2-2x+1-1\\0=3x^2-2x+0$

Now, we can easily identify 3 as a, -2 as b and 0 as c. Plug these into the quadratic formula:

$x=\frac{-b\±\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}$

I hope this helps!

8 0

2 years ago

Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0 = 2x2 + 3x – 8? Quadratic formula: x

Lynna [10]

ANSWER

1.39

EXPLANATION

The given quadratic equation is

$0 = 2 {x}^{2} + 3x - 8$

This is the same as,

$2 {x}^{2} + 3x - 8 = 0$

Comparing to

$a {x}^{2} + bx + c = 0$

We have

a=2, b=3,c=-8

Using the quadratic formula, the solution is given by:

$x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a}$

We substitute the values to get,

$x = \frac{ - 3\pm \: \sqrt{ {3}^{2} - 4(2)( - 8)} }{2(2)}$

$x = \frac{ - 3\pm \: \sqrt{ 73} }{4}$

The positive root is

$x = \frac{ - 3 + \: \sqrt{ 73} }{4} = 1.39$

to the nearest hundredth.

4 0

3 years ago

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