since it has a diameter of 28, then its radius must be half that or 14.
![\textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=14 \end{cases}\implies A=\pi (14)^2\implies A=196\pi ~\hfill \stackrel{\stackrel{semi-circle}{half~that}}{98\pi }](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D14%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Cpi%20%2814%29%5E2%5Cimplies%20A%3D196%5Cpi%20~%5Chfill%20%5Cstackrel%7B%5Cstackrel%7Bsemi-circle%7D%7Bhalf~that%7D%7D%7B98%5Cpi%20%7D)
i hope this helps you......
Very easy question.
To find x intercept: Multiply y by 0. You get x=-5.
To find y intercept: Multiply x by 0. You get y=-5.
Answer: <em><u>CAN YOU PLS MARK AS BRAINLIEST??</u></em>
a.x=11/4
b.x=6
c.x=21/2
d.x=0
Step-by-step explanation:
-2+3x+x=9-x
-2+3x+x=9
4x=9+2
4x=11
x=11/4
when you move a numerator to the other side it becomes a denominator
x+2=3/4x6
x+2=3/24
x=8-2
x=6
5-2x-12=14
2x=14-5+12
2x=21
x=21/2
1/2x=-3-1/2x+4-1
1/2x+1/2x=-3+4-1
x=0