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Liono4ka [1.6K]
3 years ago
7

The dog’s leash is 60 inches long. If the dog walks back and forth with its leash pulled tight while the leash is tied to the li

ght post, it will walk in part of a circle. If the dog’s leash rotates through 150° , how far does the dog walk ?
Arc Length=_______________
Mathematics
1 answer:
labwork [276]3 years ago
5 0

Answer:

150.08 inches

Step-by-step explanation:

The question simply requires that we find the length of the arc that the dog walks.

Its leash rotates through 150° and the length of the leash (radius) is 60 inches.

The length of an arc is given as:

L = α/360 * 2πR

where α = angle of arc

R =radius

Therefore:

L = 150/360 * 2 * π * 60

L = 150.08 inches

The dog walks 150.08 inches

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kvv77 [185]
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3 years ago
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Likurg_2 [28]

Answer:

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Step-by-step explanation:

See the steps below:)

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Nikitich [7]

Answer:

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Step-by-step explanation:

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3 years ago
Reports on a student’s ACT, SAT, or MCAT usually give the percentile as well as the actual score. The percentile is just the cum
DaniilM [7]

Answer:

The percentile is calculated with the following probability:

P(X

And using the z score we got:

P(X

So then we can conclude that 31 represent approximately the percentile 81 on the distribution given

He scored better than about 80.98 % of all MCAT takers.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X \sim N(25.3,6.5)  

Where \mu=25.3 and \sigma=6.5

And for this case we have a score of 31

The percentile is calculated with the following probability:

P(X

And using the z score we got:

P(X

So then we can conclude that 31 represent approximately the percentile 81 on the distribution given

He scored better than about 80.98 % of all MCAT takers.

6 0
3 years ago
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