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Nesterboy [21]
3 years ago
12

Find the distance between the pair of points.

Mathematics
1 answer:
Marat540 [252]3 years ago
8 0

Answer:

11 units

Step-by-step explanation:

Just trust me!

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Over the course of 6 days Tonda ran 17.22 miles She ran the same distance each day How far did Tonga run each day ?
larisa [96]

Work Progress: 17.22mile/6 days = 2.87

Tonda ran 2.87 miles each day.

5 0
3 years ago
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A candy company produces individually wrapped candies. The quality control manager for the company believes that the weight of t
zmey [24]

Answer:

option (b) 700 mg to 740 mg

Step-by-step explanation:

Data provided;

The weight of candies is approximately normally distributed with mean 720 milligrams (mg)

this means that the most of the candies weight lies around the 720 milligrams

i.e

the most of the weight will be distributed as:

Mean ± standard deviation

here, the mean is 720 milligrams

thus,

the weights will lie within the range of some standard deviation above and below the  mean and this is justified by the option (b) 700 mg to 740 mg

Hence,

the correct answer is option (b) 700 mg to 740 mg

7 0
3 years ago
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A Pitbull gave birth 6 puppies weighing 200g each. How much did they weigh all together in pounds?
Elina [12.6K]

Answer:

1,200

Step-by-step explanation:

200 x 6 = 1,200

5 0
3 years ago
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Bryn is riding his bicycle at a constant speed from school to the library. His distance from the library in kilometers x hours a
Vika [28.1K]

Answer:

The distance is 20km

Step-by-step explanation:

Given

y = 20 - 12x

Required

The distance between the\ library\ and\ the school

The function represents the distance y = 20 - 12x

So, when x = 0.

This implies that he has not started moving.

So:

y = 20 - 12 * 0

y = 20 - 0

y = 20

8 0
3 years ago
I need help with part b. I feel like there’s a catch, I want to do the first derivative test, however, I feel like there is a be
Sladkaya [172]

Answer:

The fifth degree Taylor polynomial of g(x) is increasing around x=-1

Step-by-step explanation:

Yes, you can do the derivative of the fifth degree Taylor polynomial, but notice that its derivative evaluated at x =-1 will give zero for all its terms except for the one of first order, so the calculation becomes simple:

P_5(x)=g(-1)+g'(-1)\,(x+1)+g"(-1)\, \frac{(x+1)^2}{2!} +g^{(3)}(-1)\, \frac{(x+1)^3}{3!} + g^{(4)}(-1)\, \frac{(x+1)^4}{4!} +g^{(5)}(-1)\, \frac{(x+1)^5}{5!}

and when you do its derivative:

1) the constant term renders zero,

2) the following term (term of order 1, the linear term) renders: g'(-1)\,(1) since the derivative of (x+1) is one,

3) all other terms will keep at least one factor (x+1) in their derivative, and this evaluated at x = -1 will render zero

Therefore, the only term that would give you something different from zero once evaluated at x = -1 is the derivative of that linear term. and that only non-zero term is: g'(-1)= 7 as per the information given. Therefore, the function has derivative larger than zero, then it is increasing in the vicinity of x = -1

6 0
4 years ago
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