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2 years ago

The perimeter of a regular pentagon is 17.5 inches. What is the length of each side? 3.5 in. 4 in. 5.8 in. 87.5 in.

Mathematics

1 answer:

Fantom [35]2 years ago

5 0

Answer:

3.5 in.

Step-by-step explanation:

17.5 ÷ 5 = 3.5

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18 2by5-4 1by10 find the difference

luda_lava [24]

Given:

The expression is:

$18\dfrac{2}{5}-4\dfrac{1}{10}$

To find:

The difference.

Solution:

We have,

$18\dfrac{2}{5}-4\dfrac{1}{10}$

It can be rewritten as:

$=\dfrac{90+2}{5}-\dfrac{40+1}{10}$

$=\dfrac{92}{5}-\dfrac{41}{10}$

Taking LCM, we get

$=\dfrac{184-41}{10}$

$=\dfrac{143}{10}$

$=\dfrac{140+3}{10}$

$=14\dfrac{3}{10}$

Therefore, the value of the difference is $14\dfrac{3}{10}$ .

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2 years ago

A gallon of latex paint can cover 300 square feet. Felix has a pentagonal room in which all the sides have the same lenth of 10

Shkiper50 [21]

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2 years ago

(Isosceles Triangle) 7x +3 5x + 7 С 10 ==[blank1]

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Answer:

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2 years ago

StartFraction (negative 7) squared Over (negative 7) Superscript negative 1 EndFraction

Elan Coil [88]

Answer:

-343

Step-by-step explanation:

Given the expression: $\dfrac{(-7)^2}{(-7)^{-1}}$

You will notice that the terms in the numerator and denominator have the same base (-7).

This makes it very easy to simplify by applying the division law of indices.

$\dfrac{a^x}{a^y} =a^{x-y}$

Therefore:

$\dfrac{(-7)^2}{(-7)^{-1}}=(-7)^{2-(-1)}\\=(-7)^{2+1}\\=(-7)^3\\=-7 X -7 X -7\\=-343$

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2 years ago

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