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If 6.2a=0.0143 then what is a?

Evgesh-ka [11]

6.2a = 0.0143

=> a = 0.0143/6.2

=> a = 0.0023......

3 0

3 years ago

3. Formulate 900 lbs of a 35% CP ration using Soybean Meal (46% CP) and Oats (12% CP). How many pounds of soybean meal will be u

Anarel [89]

Answer:

The amount of Soyabean = 608.82 pounds.

The amount of Oats = 900-608.82 = 291.18 pounds.

Step-by-step explanation:

Given that the Soybean Meal has 46% CP and Oats has 12% CP.

The total amount of ration is 900 lbs of 35% CP.

Let x pounds of Soyabean has been used, so,

the amount of Oats = 900-x lbs.

The CP amount in 900 lbs mixture will be equal to the sum of CP amounts in x lbs Soyabean and 900-x lbs Oats, i.e

35% of 900 = 46% of x + 12% of (900-x)

$\Rightarrow \frac{35}{100}\times 900=\frac{46}{100}\times x+\frac{12}{100}\times (900-x)$

$\Rightarrow 35\times 900 = 46x + 12\times 900 - 12 x$

$\Rightarrow 34x= 900(35-12)$

$\Rightarrow x = (900\times 23)/34$

$\Rightarrow x = 608.82$ lbs.

So, the amount of Soyabean = 608.82 pounds.

The amount of Oats = 900-608.82 = 291.18 pounds.

5 0

3 years ago

LOTS OF POINTS GIVING BRAINLIEST I NEED HELP PLEASEE

Sidana [21]

Answer:

Segment EF: y = -x + 8

Segment BC: y = -x + 2

Step-by-step explanation:

Given the two similar right triangles, ΔABC and ΔDEF, for which we must determine the slope-intercept form of the side of ΔDEF that is parallel to segment BC.

Upon observing the given diagram, we can infer the following corresponding sides:

$\displaystyle\mathsf{\overline{BC}\:\: and\:\:\overline{EF}}$

$\displaystyle\mathsf{\overline{BA}\:\: and\:\:\overline{ED}}$

$\displaystyle\mathsf{\overline{AC}\:\: and\:\:\overline{DF}}$

We must determine the slope of segment BC from ΔABC, which corresponds to segment EF from ΔDEF.

<h2>Slope of Segment BC:</h2>

In order to solve for the slope of segment BC, we can use the following slope formula:

$\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}} }$

Use the following coordinates from the given diagram:

Point B: (x₁, y₁) = (-2, 4)

Point C: (x₂, y₂) = ( 1, 1 )

Substitute these values into the slope formula:

$\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}\:=\:\frac{1\:-\:4}{1\:-\:(-2)}\:=\:\frac{-3}{1\:+\:2}\:=\:\frac{-3}{3}\:=\:-1}$

<h2>Slope of Segment EF:</h2>

Similar to how we determined the slope of segment BC, we will use the coordinates of points E and F from ΔDEF to find its slope:

Point E: (x₁, y₁) = (4, 4)

Point F: (x₂, y₂) = (6, 2)

Substitute these values into the slope formula:

$\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}\:=\:\frac{2\:-\:4}{6\:-\:4}\:=\:\frac{-2}{2}\:=\:-1}$

Our calculations show that segment BC and EF have the same slope of -1. In geometry, we know that two nonvertical lines are <u>parallel</u> if and only if they have the same slope.

Since segments BC and EF have the same slope, then it means that $\displaystyle\mathsf{\overline{BC}\:\: | |\:\:\overline{EF}}$ .

<h2>Slope-intercept form:</h2><h3><u>Segment BC:</u></h3>

The <u>y-intercept</u> is the point on the graph where it crosses the y-axis. Thus, it is the value of "y" when x = 0.

Using the slope of segment BC, m = -1, and the coordinates of point C, (1, 1), substitute these values into the <u>slope-intercept form</u> (y = mx + b) to solve for the y-intercept, <em>b. </em>

y = mx + b

1 = -1( 1 ) + b

1 = -1 + b

Add 1 to both sides to isolate b:

1 + 1 = -1 + 1 + b

2 = b

Hence, the <u><em>y-intercept</em></u> of segment BC is: <em>b</em> = 2.

Therefore, the linear equation in <u>slope-intercept form of segment BC</u> is:

⇒ y = -x + 2.

<h3><u /></h3><h3><u>Segment EF:</u></h3>

Using the slope of segment EF, <em>m</em> = -1, and the coordinates of point E, (4, 4), substitute these values into the <u>slope-intercept form</u> to solve for the y-intercept, <em>b. </em>

y = mx + b

4 = -1( 4 ) + b

4 = -4 + b

Add 4 to both sides to isolate b:

4 + 4 = -4 + 4 + b

8 = b

Hence, the <u><em>y-intercept</em></u> of segment BC is: <em>b</em> = 8.

Therefore, the linear equation in <u>slope-intercept form of segment EF</u> is:

⇒ y = -x + 8.

8 0

3 years ago

The residents of a city voted on whether to raise property taxes. The ratio of yes votes to no votes was 7 to 4. If there were 4

Elena-2011 [213]

Answer:

2628

Step-by-step explanation:

7/4 = 1.75 = 175%

x is the number of no votes

4599/x = 7/4

x = 4599/(7/4)

x = 2628

5 0

2 years ago

Altitudes AA1 and BB1 are drawn in acute △ABC. Prove that A1C·BC=B1C·AC

Sophie [7]

Answer:

See the attached figure which represents the problem.

As shown, AA₁ and BB₁ are the altitudes in acute △ABC.

△AA₁C is a right triangle at A₁

So, Cos x = adjacent/hypotenuse = A₁C/AC ⇒(1)

△BB₁C is a right triangle at B₁

So, Cos x = adjacent/hypotenuse = B₁C/BC ⇒(2)

From (1) and (2)

∴ A₁C/AC = B₁C/BC

using scissors method

∴ A₁C · BC = B₁C · AC

7 0

3 years ago