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4 years ago

1)Split 36 into the ratio 5:4

Mathematics

2 answers:

daser333 [38]4 years ago

8 0

6,9,19,26,68 so yeah

fredd [130]4 years ago

5 0

Add the two ratio numbers together then divide the original by that.

Then multiply that answer by each ratio number.

1)Split 36 into the ratio 5:4

5+4 = 9

36/9 = 4

5*4 = 20

4 * 4 = 16

It is split 20:16

2)split 45 into the ratio 7:2

7+2 = 9

45 / 9 = 5

7 *5 = 35

2*5 = 10

It is split

35:10

3)split 112 into the ratio 5:9

5 +9 = 14

112 / 14 = 8

5*8 = 40

9*8 = 72

It is split 40:72

4)split 66 into the ratio 4:7

4+7 = 11

66/11 = 6

4*6 = 24

7*6 =42

It is split 24:42

5)split 42 into the ratio 5:2

5+2 = 7

72 / 7 = 6

5*6 = 30

2*6 = 12

It is split 30:12

6)split 65 into the ratio 7:6

7+6 = 13

65 / 13 = 5

7 *5 = 35

6*5 = 30

It is split 35:30

7)split 99 into the ratio 4:7

4+7 = 11

99 / 11 = 9

4*9 = 36

7 *9 = 63

It is split 36:63

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A regular octagonal pyramid has a base edge of 3m and a lateral area of 60m^2. Find its slant height.

Olin [163]

Octagon = 8-side polygon

Find area of 1 triangle:
Area of one side triangle = 60 ÷ 8 = 7.5 m²

Given area and length, find height:
Area of each triangle = 7.6 m²
Length of each triangle = 3m

Area = 1/2 x base x height
7.5 = 1/2 x 3 x height
Heigth = 5m

Answer: Slanted Height = 5 m

4 0

3 years ago

Math help Please!!!!

GalinKa [24]

Part A. What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7?

Rewrite the equation −2y=3x+7 in the form $y=-\dfrac{3}{2}x-\dfrac{7}{2}.$ Here the slope of the given line is $m_1=-\dfrac{3}{2}.$ If $m_2$ is the slope of perpendicular line, then

$m_1\cdot m_2=-1,\\ \\m_2=-\dfrac{1}{m_1}=\dfrac{2}{3}.$

Answer 1: $\dfrac{2}{3}$

Part B. The slope of the line y=−2x+3 is -2. Since $-\dfrac{3}{2}\neq -2\quad \text{and}\quad \dfrac{2}{3}\neq -2,$ then lines from part A are not parallel to line a.

Since $-2\cdot \left(-\dfrac{3}{2}\right)=3\neq -1\quad \text{and}\quad -2\cdot \dfrac{2}{3}=-\dfrac{4}{3}\neq -1,$ both lines are not perpendicular to line a.

Answer 2: Neither parallel nor perpendicular to line a

Part C. The line parallel to the line 2x+5y=10 has the equation 2x+5y=b. This line passes through the point (5,-4), then

2·5+5·(-4)=b,

10-20=b,

b=-10.

Answer 3: 2x+5y=-10.

Part D. The slope of the line $y=\dfrac{x}{4}+5$ is $\dfrac{1}{4}.$ Then the slope of perpendicular line is -4 and the equation of the perpendicular line is y=-4x+b. This line passes through the point (2,7), then