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Dmitrij [34]
3 years ago
5

1)Split 36 into the ratio 5:4

Mathematics
2 answers:
daser333 [38]3 years ago
8 0
6,9,19,26,68 so yeah
fredd [130]3 years ago
5 0

Add the two ratio numbers together then divide the original by that.

Then multiply that answer by each ratio number.

1)Split 36 into the ratio 5:4

5+4 = 9

36/9 = 4

5*4 = 20

4 * 4 = 16

It is split 20:16

2)split 45 into the ratio 7:2

7+2 = 9

45 / 9 = 5

7 *5 = 35

2*5 = 10

It is split

35:10

3)split 112 into the ratio 5:9

5 +9 = 14

112 / 14 = 8

5*8 = 40

9*8 = 72

It is split 40:72

4)split 66 into the ratio 4:7

4+7 = 11

66/11 = 6

4*6 = 24

7*6 =42

It is split 24:42

5)split 42 into the ratio 5:2

5+2 = 7

72 / 7 = 6

5*6 = 30

2*6 = 12

It is split 30:12

6)split 65 into the ratio 7:6

7+6 = 13

65 / 13 = 5

7 *5 = 35

6*5 = 30

It is split 35:30

7)split 99 into the ratio 4:7

4+7 = 11

99 / 11 = 9

4*9 = 36

7 *9 = 63

It is split 36:63

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A packet contains 24 pens. Henry and Alice share them in the ratio 3:5. How many does Alice receive
vova2212 [387]
Alice receives 9 out of the 24 pens.
7 0
3 years ago
A school debate team has four girls and six boys. A total of four of the team members will be chosen to participate in the distr
alex41 [277]
Procedure:

1) calculate the number of diferent teams of four members that can be formed (with the ten persons)
2) calculate the number of teams tha meet the specification (two girls and two boys)
3) Divide the positive events by the total number of events: this is the result of 2) by the result in 1)

Solution

1) the number of teams of four members that can be formed are:

10*9*8*7 / (4*3*2*1) = 210

2) Number of different teams with 2 boys and 2 girls = ways of chosing 2 boys * ways of chosing 2 girls

Ways of chosing 2 boys = 6*5/2 = 15
Ways of chosing 2 girls = 4*3/2 = 6

Number of different teams with 2 boys and 2 girls = 15 * 6 = 90

3) probability of choosing one of the 90 teams formed by 2 boys and 2 girls:

90/210 = 3/7
 
7 0
3 years ago
ms evans went to the store to buy some cupcakes. she brought 129 cupcakes. she wants to put 5 cupcakes in each box.how many boxe
NeTakaya
129 divided by 5 is equal to 25 with a remainder of 4. 

This means that she will need a total of 26 boxes, but only 25 of them will have 5 cupcakes in them. The last one will have 4 cupcakes.
6 0
3 years ago
Read 2 more answers
What is 94 times 100​
meriva
<h2>ANSWER:</h2>

<u><em></em></u>

<u><em>9400</em></u>

<h2>Step-by-step explanation:</h2><h3><u><em></em></u></h3><h3><u><em>Take 94 x 100 and get = 9400</em></u></h3><h2><u><em /></u></h2>

<u><em>Thank you for asking this great question need any other help please let me know by commenting below I'd be glad to help.</em></u>

<u><em /></u>

<u><em> I'd also greatly appreciate you if you mark me as brainliest and click that thanks button.( optional )</em></u>

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<u><em>Your brainly friend ( lauralit1 )</em></u>

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<u><em /></u>

3 0
3 years ago
Read 2 more answers
Someone help me please!
andriy [413]

Answer:

To solve the first inequality, you need to subtract 6 from both sides of the inequality, to obtain 4n≤12. This can then be cancelled down to n≤3 by dividing both sides by 4. To solve the second inequality, we first need to eliminate the fraction by multiplying both sides of the inequality by the denominator, obtaining 5n>n^2+4. Since this inequality involves a quadratic expression, we need to convert it into the form of an^2+bn+c<0 before attempting to solve it. In this case, we subtract 5n from both sides of the inequality to obtain n^2-5n+4<0. The next step is to factorise this inequality. To factorise we must find two numbers that can be added to obtain -5 and that can be multiplied to obtain 4. Quick mental mathematics will tell you that these two numbers are -4 and -1 (for inequalities that are more difficult to factorise mentally, you can just use the quadratic equation that can be found in your data booklet) so we can write the inequality as (n-4)(n-1)<0. For inequalities where the co-efficient of n^2 is positive and the the inequality is <0, the range of n must be between the two values of n whereby the factorised expresion equals zero, which are n=1 and n=4. Therefore, the solution is 1<n<4 and we can check this by substituting in n=3, which satisfies the inequality since (3-4)(3-1)=-2<0. Since n is an integer, the expressions n≤3 and n<4 are the same. Therefore, we can write the final answer as either 1<n<4, or n>1 and n≤3.

5 0
3 years ago
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