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enyata [817]
2 years ago
8

A bag contains 3 red,4 green, and 5 blue marbles. Three marbles are drawn at random. What is the probability that all three are

of different colors?.
Mathematics
1 answer:
Reptile [31]2 years ago
8 0

Answer:

1/22

Step-by-step explanation:

assuming that the marbles drawn are not replaced:

P(red) = 3/12 or 1/4

P(green) = 4/11

P(blue) = 5/10 or 1/2

multiply the probabilities together:

1/4 x 4/11 x 1/2 = 1/22

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Step-by-step explanation:

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Answer:

8

Step-by-step explanation:

The 110 degree angle is oppoiste to the angle across it.

Using PLT-C the other angle on the bottom of it should be 70 degrees.

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14(8)-2 = 110

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2 years ago
Which equation represents y = −x2 + 6x + 7 in vertex form? y = −(x + 3)2 + 4 y = −(x − 3)2 + 10 y = −(x + 3)2 + 2 y = −(x − 3)2
Colt1911 [192]

\text{The vertex form:}\ y=a(x-h)^2+k\\\\f(x)=ax^2+bx+c\to h=\dfrac{-b}{2a},\ k=f(h)\\\\\text{We have}\ y=-x^2+6x+7\to f(x)=-x^2+6x+7\\\\a=-1,\ b=6,\ c=7\\\\h=\dfrac{-6}{2(-1)}=\dfrac{-6}{-2}=3\\\\k=f(3)=-3^2+6(3)+7=-9+18+7=16\\\\Answer:\ \boxed{y=-(x-3)^2+16}

8 0
3 years ago
Which relationship is always true for the angles x, y, and z of triangle ABC?
noname [10]

Answer:

y + z = x

Step-by-step explanation:

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w + y + z = w + x

We can then cancel w on each side:

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Hope this helps! :)

8 0
2 years ago
How do I solve this?
Sonbull [250]

The question is somewhat poorly posed because the equation doesn't involve <em>θ</em> at all. I assume the author meant to use <em>x</em>.

sec(<em>x</em>) = csc(<em>x</em>)

By definition of secant and cosecant,

1/cos(<em>x</em>) = 1/sin(<em>x</em>)

Multiply both sides by sin(<em>x</em>) :

sin(<em>x</em>)/cos(<em>x</em>) = sin(<em>x</em>)/sin(<em>x</em>)

As long as sin(<em>x</em>) ≠ 0, this reduces to

sin(<em>x</em>)/cos(<em>x</em>) = 1

By definition of tangent,

tan(<em>x</em>) = 1

Solve for <em>x</em> :

<em>x</em> = arctan(1) + <em>nπ</em>

<em>x</em> = <em>π</em>/4 + <em>nπ</em>

(where <em>n</em> is any integer)

In the interval 0 ≤ <em>x</em> ≤ 2<em>π</em>, you get 2 solutions when <em>n</em> = 0 and <em>n</em> = 1 of

<em>x</em> = <em>π</em>/4   <u>or</u>   <em>x</em> = 5<em>π</em>/4

5 0
2 years ago
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