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2 years ago

8

two variables have a positive linear correlation. does the dependent variable increase or decrease as the independent variable i

ncreases?

1 answer:

n200080 [17]2 years ago

6 0

The dependent variable will also increase hope this helps

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Find the vertex for the equation: y=-2x^2+16x-31

Nutka1998 [239]

Answer:

Vertex is (4,1)

Step-by-step explanation:

x=-b/2a so you need to first divide the b (second term) by the a (first term) so you should get 1 as your new a and -8 as your new b. Negative (-8) is just 8 then divide that by 2(1) which is just 2 which equals 4. That is your x. To find your y, you plug your x back into the original equation and then solve it. Hope this helps!

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3 years ago

A pipe is 36 feet long. It needs to be cut into pieces that are each 3/4 feet long. How many pieces can be made from the pipe?

Ket [755]

108/4 = 27 pieces you multiply 36 x 3 = 108 and the denominator stays the same so 108/4 equals to 27 pieces

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3 years ago

Find the midpoint of (-5,12) and (3,-6)

exis [7]

Answer:

mid point: (4,5)

hope that helps :)

Step-by-step explanation:

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3 years ago

Read 2 more answers

Cos2x + sin2 x =______

Alenkasestr [34]

Cos²(x) + sin²(x)
¹/₂[1 - cos(2x)] + ¹/₂[1 + cos(2x)]
[¹/₂ - ¹/₂cos(2x)] + [¹/₂ + ¹/₂cos(2x)]
¹/₂ + ¹/₂ - ¹/₂cos(2x) + ¹/₂cos(2x)
1

8 0

3 years ago

Find the exact values of sin2 θ for cos θ = 3/18 on the interval 0° ≤ θ ≤ 90°

mote1985 [20]

Answer:

$sin(2\theta)=\frac{\sqrt{35} }{18}$

Step-by-step explanation:

Recall the formula for the sine of the double angle:

$sin(2\theta)=2*sin(\theta)*cos(\theta)$

we know that $cos(\theta)=\frac{3}{18}$ , and that $\theta$ is in the interval between 0 and 90 degrees, where both the functions sine and cosine are non-negative numbers. Based on such, we can find using the Pythagorean trigonometric property that relates sine and cosine of the same angle, what $sin(\theta)$ is:

$cos^2(\theta)+sin^2(\theta)=1\\sin^2(\theta)=1-cos^2(\theta)\\sin(\theta)=\sqrt{1-cos^2(\theta)} \\sin(\theta)=\sqrt{1-(\frac{3}{18} )^2}\\sin(\theta)=\sqrt{1-\frac{9}{324} }\\sin(\theta)=\sqrt{\frac{324-9}{324} }\\sin(\theta)=\sqrt{\frac{315}{324} }\\\\sin(\theta)=\frac{3}{18}\sqrt{35 }$

With this information, we can now complete the value of the sine of the double angle requested:

$sin(2\theta)=2*sin(\theta)*cos(\theta)\\sin(2\theta)=2*\frac{3}{18} \,\sqrt{35} \,\frac{3}{18}\\sin(2\theta)=\frac{2*3*3}{18*18}\,\sqrt{35} \\sin(2\theta)=\frac{\sqrt{35} }{18}$

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3 years ago