PLEASE HELP! I"LL MARK BRAINLIEST!!!!

Eric’s average income for the first 4 months of the year is $1,450.25, what must be his

drek231 [11]

Answer:

Average income of Eric for the remaining 8 months = $\$1946$

Step-by-step explanation:

Given: Average income of Eric for the first 4 months of the year is equal to $1,450.25

To find: average income for the remaining 8 months so that his average income for the year is $1,780.75

Solution:

Average income = Total income for the year/Total number of months

Average income of Eric for the first 4 months = $1,450.25

So,

Total income of Eric for the first 4 months = 1,450.25 × 4 = 5801

Let x denotes total income of Eric for the remaining 8 months

Total income for the year = 5801 + x

Therefore,

Average income for the year = $\frac{5801+x}{12}$

Also, average income for the year is $1,780.75

$1780.75=\frac{5801+x}{12}\\1780.75\times 12=5801+x\\21369=5801+x\\21369-5801=x\\15568=x$

Total income of Eric for the remaining 8 months = $15568

Average income of Eric for the remaining 8 months = $\frac{15568}{8}=\$1946$

7 0

3 years ago

The measure of each interior angle in a regular quadrilateral is ___°.

gayaneshka [121]

Answer:

if it is a regular quadrilateral and each angle is equal then its 90 degrees

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The area of trapezoid TRAP is 100. Furthermore, TR=32, AP=8, and TP=RA. If

saw5 [17]

Answer:

TP = 13

Step-by-step explanation:

The height of the trapezoid can be found from the area formula:

A = (1/2)(b1 +b2)h

h = 2A/(b1 +b2) = 2(100)/(32 +8)

h = 5

The horizontal length of each triangular end of the trapezoid is ...

(32 -8)/2 = 24/2 = 12

so the hypotenuse of the triangular end of the trapezoid is ...

TP = √(12^2 +5^2) = √169

TP = 13

The sides of the trapezoid have length 13 units.

4 0

3 years ago

. Let X and Y be random variables of possible percent returns (0%, 10%,

bazaltina [42]

(a) The marginal distribution of X is

Pr(X = x) = ∑ Pr(X = x, Y = y)

… = 0.0625 + 0.0625 + 0.0625 + 0.0625

… = 0.25

That is, the first equality follows from the law of total probability, with the sum taken over y from {0, 5, 10, 15}. Each probability Pr(X = x, Y = y) is given in the table to be 0.0625.

Similarly, the marginal distribution of Y is

Pr(Y = y) = 0.25

(b) Yes, they're independent because

Pr(X = x, Y = y) = 0.0625,

and

Pr(X = x) Pr(Y = y) = 0.25 • 0.25 = 0.0625.

(c) The mean of X is

E[X] = ∑ x Pr(X = x)

… = 0.25 ∑ x

… = 0.25 (0 + 5 + 10 + 15)

… = 7.5

and you would find the same mean for Y,

E[Y] = 7.5

The variance of X is

V[X] = E[X^2] - E[X]^2

… = (∑ x^2 Pr(X = x)) - 7.5^2

… = 0.25 (∑ x^2) - 56.25

… = 0.25 (0^2 + 5^2 + 10^2 + 15^2) - 56.25

… = 31.25

and similarly,

V[Y] = 31.25

(each sum is taken with x and y from {0, 5, 10, 15})

7 0

3 years ago

90 is 1/10 of what. Plz tell me

Novay_Z [31]

90 is 1/10 of the number 900.

6 0

3 years ago