Ask question

Ask question

All categories

andreyandreev [35.5K]

3 years ago

8

Luke hiked 6 1/4 miles. Joana hiked 2 1/ 5 times as far. how far did joana hike?

1 answer:

mel-nik [20]3 years ago

7 0

Answer:

13.75 or 13 3/4

Step-by-step explanation:

You might be interested in

Which explanation is an accurate way to describe the solution to a system of equations by using a graph?

Volgvan

The correct answer for this question is this one: "The location (x, y) where the lines intersect is a solution to a system of equations." <span>This is the explanation that is an accurate way to describe the solution to a system of equations by using a graph. </span>Hope this helps answer your question and have a nice day ahead.

8 0

3 years ago

Match the following items.

ivann1987 [24]

<u>Given</u>

AC = BC

<u>Substitution</u>

∠1 = ∠3

<u>Base ∠'s of isosceles triangle =</u>

∠1 = ∠3

<u>Vertical angles =</u>

∠2 = ∠3

7 0

2 years ago

Read 2 more answers

Find the value of x. <br> View picture for full problem. Please and thank you!<br> m<2 = 6x + 12.

Karo-lina-s [1.5K]

Answer:

x = 8

Step-by-step explanation:

All the sides are equal. So, it is an equilateral triangle. So, all angles are 60 each

6x + 12 = 60

6x = 60 - 12

6x = 48

x = 48/6

x = 8

4 0

2 years ago

Listed below are speeds (mi/h) measured from southbound traffic on I-280 near Cupertino, California (based on data from SigAlert

adell [148]

Answer:

Option (B) is the correct answer to the following question.

Step-by-step explanation:

Step-1: We have to find the Mean of the series.

The series is Given in the question 62 61 61 57 61 54 59 58 59 69 60 67.

$Mean(\overline{x})=\frac{62+61+61+57+61+54+59+58+59+69+60+67}{12}$ $= 60.67$

Step-2: We have to find the Standard Deviation.

Let Standard Deviation be x.

Formula of Standard Deviation is: $s= \sqrt{\frac{\sum(x_{i}+\overline{x})}{n-1}}$

Put value in formula of Standard Deviation,

$s= \sqrt{\frac{(62+60.67)^{2}+(61+60.67)^{2}+(61+60.67)^{2}+(57+60.67)^{2}+....(67+60.67)^{2}}{n-1}}$ = 40.75

Step-3: Then, we have to find the critical value by chi-square.

$X_{1-\alpha/2}^{2}=3.82$

$X_{1-\alpha/2}^{2}=21.92$

Then, find the confidence interval which is 95%.

$\sqrt{\frac{(n-1).s^2}{X_{\alpha/2}^{2}} } = \sqrt{\frac{12-1}{21.92}.(4.075)^2 }\approx2.8868 \\ i.e 2.9$

$\sqrt{\frac{(n-1).s^2}{X_{\alpha/2}^{2}} } = \sqrt{\frac{12-1}{3.816}.(4.075)^2 }\approx6.9188 \\ i.e 6.9$

5 0

3 years ago

Help me to find the slope and t-intercept please asap

Ludmilka [50]

Answer:

4/7x - 5 ________________________________________

8 0

2 years ago