Let the slower train's velocity be x-21
Let the faster train's velocity be x
We know that the approach speed is the sum of both speeds, so x+x -21= 2x-21.
The approach rate is given by Distance/time = 471/3 = 157mpH
x+x-21=157
2x=157+21
2x=178
x=89mph
The slower train is travelling 89-21 = 68mph
The faster train is travelling 89mph.
Answer:
x is 11
Step-by-step explanation:
We know the slope (3/4) and a point (3,-4), so we can use point-slope form (y-y1=m(x-x1)
Substitute the numbers into the equation
y--4=3/4(x-3)
simplify
y+4=3/4(x-3)
do the distributive property
y+4=3/4x-9/4
subtract 4 from both sides
y=3/4x-25/4
this is the equation of the line.
Since it says that (x,2) is a point in the equation, we can substitute it into the equation
2=3/4x-25/4
add 25/4 to both sides
33/4=3/4x
multiply by 4/3
11=x
we can double check by plugging (11,2) into the equation of the line.
2=3/4(11)-25/4
2=33/4-25/4
2=2
it works! :)
Hope this helps!
Well it's a dare so I guess I'll do it.
Agree with the one at the top it’s 36
The answer is 79 im sure of it
