1) subtract 2y in both sides: (7y-2y)-6=(2y-2y)+8 which is 5y-6=8
2) Add 6 to both sides: 5y(-6+6)=8+6 which is 5y=14
3) Divide 5 on both sides: 5y/5=14/5 which is y=14/5 or y=2.8 or y=2 4/5
Answer:
(12,-6)
Step-by-step explanation:
we have
----> inequality A
---> inequality B
we know that
If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)
<u><em>Verify each point</em></u>
Substitute the value of x and the value of y of each ordered pair in the inequality A and in the inequality B
case 1) (0,-1)
Inequality A

----> is true
Inequality B

----> is not true
therefore
The ordered pair is not a solution of the system
case 2) (0,3)
Inequality A

----> is true
Inequality B

----> is not true
therefore
The ordered pair is not a solution of the system
case 3) (-6,-6)
Inequality A

----> is true
Inequality B

----> is not true
therefore
The ordered pair is not a solution of the system
case 4) (12,-6)
Inequality A

----> is true
Inequality B

----> is true
therefore
The ordered pair is a solution of the system (makes true both inequalities)
Answer:
x=0.5
y = 10.5
Step-by-step explanation:
y = 3x + 7
y = 5x + 8
3x + 7 = 5x + 8
3x - 5x= 8 - 7
2x = 1
x= 1/2
x=0.5
y = 5x + 8
y = 5(0.5) + 8
y = 2.5 + 8
y = 10.5