V=(4/3)pir^3
find smaller
V=(4/3)pi8^3
V=(4/3)pi512
V=(2048/3)pi
twice of that
Vbig=2*(2048/3)pi
Vbig=(4096/3)pi
find radius
(4096/3)pi=(4/3)pir^3
divide both sides by pi
(4096/3)=(4/3)r^3
times both sides by 3
4096=4r^3
divide both sides by 4
1024=r^3
cube root both sides
8∛2=r
aprox
10.0794
the answer you are looking for is 8∛2 or 10.0794in or something close to that
Answer:
The 96% confidence interval estimate for the mean daily number of minutes that BYU students spend on their phones in fall 2019 is between 306.65 minutes and 317.35 minutes.
Step-by-step explanation:
Confidence interval normal
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
That is z with a pvalue of
, so Z = 2.054.
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 312 - 5.35 = 306.65 minutes
The upper end of the interval is the sample mean added to M. So it is 312 + 5.35 = 317.35 minutes
The 96% confidence interval estimate for the mean daily number of minutes that BYU students spend on their phones in fall 2019 is between 306.65 minutes and 317.35 minutes.
HELLO DEAR,
GIVEN:-
8cos²x + cosx - 9
8cos²x + 9cosx - 8cosx - 9
cosx(8cosx + 9) - (8cosx + 9)
(cosx - 1)(8cosx + 9)
I HOPE ITS HELP YOU DEAR,
THANKS
Step-by-step explanation:









