Question

Sin x cos x = -cos x Find all angles that satisfy the equation below

Answer 1

Answer:

$x=90^\circ,270^\circ$

Step-by-step explanation:

$sinxcosx=-cosx$

$sinxcosx+cosx=0$

$cosx(sinx+1)=0$

$cosx=0$

$x=90,270$

$sinx+1=0$

$sinx=-1$

$x=270$

Therefore, the angles that satisfy the equation are $x=90^\circ,270^\circ$