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Elenna [48]
2 years ago
14

Find m c!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Law Incorporation [45]2 years ago
5 0

Answer:

50

Step-by-step explanation:

62+68 is 130. 180-130 is 50

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Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. Thi
Mariana [72]

Answer:

a. Mean: 9.5.

Standard deviation: 2.18.

b. The critical value for signficantly low girl births is 5.14.

The critical value for signficantly high girl births is 13.86.

Step-by-step explanation:

a) If we take a sample of 19 births, all with individual probability of 0.5, we have a random binomial variable with n=19 and p=0.5.

This random variable will have mean and standard deviation calculated as:

\mu=n\cdot p=19\cdot0.5=9.5\\\\\sigma=\sqrt{np(1-p)}=\sqrt{19\cdot0.5\cdpot0.5}=\sqrt{4.75}=2.18

b) Range rule of thumb: The standard deviation is approximately a quarter of the range, difference between the maximum and minimum value.

The range rule of thumb tells us that the expected minimum and maximum value are 2 standards deviation below or above, respectively, from the mean.

Then, the extreme expected values are:

Min=\mu-2\sigma=9.5-2\cdot2.18=9.5-4.36=5.14\\\\Max=\mu+2\sigma=9.5+2\cdot2.18=9.5+4.36=13.86

The critical value for signficantly low girl births is 5.14.

The critical value for signficantly high girl births is 13.86.

6 0
3 years ago
L shcool W clash royale ​
lianna [129]

Answer:

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8 0
3 years ago
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Enter the number of complex zeros for the polynomial function in the box. f(x)=x3−96x2+400
ioda

Solution:

There is no (zero) complex zeros for the given polynomial.

Explanation:

We apply Descartes' rule of sign to identify the number of complex roots.

The given polynomial is f(x)=x^3-96x^2+400

Let us see the number of sign changes in f(x)

+,-,+

There are 2 sign changes in f(x). One from plus to minus and second from plus to minus. Hence, there 2 or 0 positive roots.

Now, let us see the number of sign changes in f(-x)

f(-x)=-x^3-96x^2+400

-,-,+

There are only one sign change. Hence, there will be 1 negative roots.

The degree of the polynomial is 3. Hence, there will be exactly 3 zeros.

Therefore, the possible numbers of zeros are

2 positive, 1 negative and 0 complex

0 positive, 1 negative and 2 complex.

Hence, possible number of complex zeros are 0 and 2.

Now, we graph the function in xy plane and see that the graph cuts the x axis at three points. It means all the zeros are real , which is the case of first possibility (2 positive, 1 negative and 0 complex).

Hence, the number of complex zeros for the given polynomial is zero.

5 0
4 years ago
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Please show step by step answer NO MIXED NUMBER/DECIMAL ANSWERS!!!
PolarNik [594]

Answer:

Step-by-step explanation:

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2 years ago
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Find the equation of the line that is parallel to y = -7x + 2 and contains the point (-5,32)​
photoshop1234 [79]

Answer:

Y=-7x-3

Step-by-step explanation:

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3 years ago
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