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3 years ago

Which expression is equivalent to 36a-12b? 3(6a-2b). 6(6a-2b). 3(6a+2b). 6(6a+2b)

Mathematics

2 answers:

exis [7]3 years ago

7 0

Answer:

6(6a-2b)

Step-by-step explanation:

if you multiply the 6 by what's in parenthesis you get 36a-12b

Maurinko [17]3 years ago

4 0

Answer:

6(6a-2b)

Step-by-step explanation:

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Paladinen [302]

Take option 2.
Let n=2^30
Then:
ln n=ln 2^30=30 ln 2
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3 years ago

Who is the general information of acounting

Anettt [7]

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2 years ago

Construct a 99% confidence interval for the population mean, mu. Assume the population has a normal distribution. A group of 1

Zarrin [17]

Answer:

99% confidence interval for the population mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean age of selected students = 22.4 years

s = sample standard deviation = 3.8 years

n = sample of students = 19

$\mu$ = population mean

<em>Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.878 < $t_1_8$ < 2.878) = 0.99 {As the critical value of t at 18 degree of

freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.878) = 0.99

P( $-2.878 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.878 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

P( $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ) = 0.99

<u>99% confidence interval for</u> $\mu$ = [ $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ , $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ]

= [ $22.4 -2.878 \times {\frac{3.8}{\sqrt{19} }$ , $22.4 +2.878 \times {\frac{3.8}{\sqrt{19} }$ ]

= [19.891 , 24.909]

Therefore, 99% confidence interval for the population mean is [19.891 , 24.909].

6 0

3 years ago

What is the answer to 132.55=5 (0.04m+21.70+0.10(21.70))

postnew [5]

132.55=5(.04m+2+.7+0.1(21.7))>>>m=66

8 0

3 years ago

What are the answers

Shalnov [3]

Slope formula:
y2-y1
-------
x2-x1
48)
1-3 -2
---- = ----
-2-4 -6

So the slope of MN is 1/3

5 0

3 years ago

Read 2 more answers