Question

Given the equation: x^2+6x+8=0

Answer 1

Answer:

Use the completing the square method

which is

(x+ (b/2))^2 - (b/2)^2 + c

x^2+6x+8 = 0

a = 1 b = 6 c = 8

b/2 = 3

(x+3)^2 - 9 + 8 = 0

becomes

(x+3)^2 -1 = 0

which becomes

(x+3)^2 = 1

ADDITIONAL:

i don’t know why they said (x-h) since there are no negatives in this

let me explain

(x-h) ^2 is the same as (x-h)(x-h) which leaves us with

x^2 - 2xh + h

but the equation we start with is

x^2 + 6x + 8 = 0

look at the signs

the middle term’s one is different