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Pavlova-9 [17]
3 years ago
7

An object has an area of 12 square centimeters. what could the length and width be

Mathematics
2 answers:
Serhud [2]3 years ago
8 0
3 and 4 or 6 and 2 because 3x4=12 or 6x2=12
LUCKY_DIMON [66]3 years ago
3 0
The length and width can 6 and 2 or 3 and 4.
example: 3x4=12
6x2=12
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Can u guys help me pls ill give u 20 points
Veseljchak [2.6K]

Answer:

Its either L or N im not sure but if i had to guess out of the two i think its L.

Step-by-step explanation:

6 0
3 years ago
En una muestra de 50 restaurantes de comida rápida, la venta media fue de $3.000, y la desviación estándar, $200. El intervalo d
Step2247 [10]

Respuesta:

(2945.411; 3054.589)

Explicación paso a paso:

Dado ;

Tamaño de la muestra, n = 50

Media, xbar = 3000

Desviación estándar, s = 200

Nivel de confianza, Zcrítico al 95% = 1,96

El intervalo de confianza se define como:

Xbar ± margen de error

Margen de error = Zcrítico * s / sqrt (n)

Margen de error = 1,96 * 200 / sqrt (50)

Margen de error = 54.589

Límite inferior = (3000 - 54.589) = 2945.411

Límite superior = (3000 + 54.589) = 3054.589

(2945.411; 3054.589)

8 0
3 years ago
(Pythagorean theorem)
shusha [124]

Answer:

S ≈ 16.49 cm and R ≈ 16.76 cm

Step-by-step explanation:

We are given that:

Length = 16 cm

Width = 4 cm

Height = 3 cm

Thus,

The diagonal S of the bottom side is given by pythagoras theorem;

S² = 16² + 4²

S² = 256 + 16

S² = 272

S = √272

S ≈ 16.49 cm

Since we now have the bottom diagonal, then we can use Pythagoras Theorem to find the diagonal "R" of the box:

So, R² = S² + 3²

R² = (√272)² + 9

R² = 272 + 9

R = √281

R ≈ 16.76 cm

8 0
3 years ago
3 less than the quotient of a number y and 4
mr Goodwill [35]

3 less than the quotient of a number y and 4

3       <        y / 4

3    <     y/4

x 4          x 4

12 < y

6 0
3 years ago
Which expression is equivalent to 5a+20? A: 5(5a+4). B: 5(a+4). C: 5(a+20). D: 5(a+1)
guajiro [1.7K]

Answer:

5(a+4)

Step-by-step explanation:

expression is equivalent to 5a+20

To get the equivalent expression we need to factor the given expression

5a+ 20

5a can be written as 5 * a

20 can be written as 5*2*2

WE can see that common factor is 5 for both 5a and 20

So GCF is 5

Now we factor out GCF 5

WE put 5 outside and write all the left of factors inside the parenthesis

5a +20

5 (a+2*2)

5(a+4)

4 0
4 years ago
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