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MA_775_DIABLO [31]
3 years ago
14

15x + 5 = 50 Please help!

Mathematics
2 answers:
andreev551 [17]3 years ago
8 0

\begin{gathered}\\ \sf\longmapsto 15x+5=50\end{gathered}

\begin{gathered}\\ \sf\longmapsto 15x=50-5\end{gathered}

\begin{gathered}\\ \sf\longmapsto 15x=45\end{gathered}

\begin{gathered}\\ \sf\longmapsto ⚘x=3\end{gathered}

Bess [88]3 years ago
6 0

Answer:

x = 3

Step-by-step explanation:

15x + 5 = 50

=> 15x = 45

=> x = 3

Hoped this helped.

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Serggg [28]
A = 18
You need to
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a = - 3/2 x 12
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4 years ago
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3 years ago
50 points! Please help asap! Write the equation of the perpendicular bisector of the line AB given endpoints A(3,-3) and B(1,-1)
Elza [17]

Answer:

  • y = x - 4

Step-by-step explanation:

Given AB with coordinates A(3, -3) and B(1, -1)

Perpendicular bisector passes through midpoint of the segment.

<u>Midpoint of AB has coordinates:</u>

  • x = (3 + 1)/2 = 2, y = (-3 - 1)/2 = -2

<u>Slope of AB</u>

  • m = (-1 + 3)/(1 - 3) = 2/-2 = -1

<u>Slope of the perpendicular line is:</u>

  • -1/m = -1/-1 = 1

<u>The equation of the line in point-slope form:</u>

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<u>Converted into slope-intercept form:</u>

  • y = x - 4

4 0
3 years ago
Simplify 8(xy + 8) + 1.
kobusy [5.1K]
Look at the picture.

I hope this helps!

5 0
3 years ago
Read 2 more answers
Write a situation for 15x-20&lt;130 and solve
Len [333]
15x-20\ \textless \ 130 \\ \\ 15x \ \textless \  130 + 20 \\ \\ 15x \ \textless \  150 \\ \\ x \ \textless \   \frac{150}{15} \\ \\ x \ \textless \  10 \\ \\

Answer: x < 10 
3 0
3 years ago
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