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Xelga [282]
2 years ago
7

Solve the following equation simultaneously 1/x-5/y=7, 2/x+1/y=3​

Mathematics
1 answer:
maria [59]2 years ago
6 0

Answer:

  (x, y) = (1/2, -1)

Step-by-step explanation:

Subtracting twice the first equation from the second gives ...

  (2/x +1/y) -2(1/x -5/y) = (3) -2(7)

  11/y = -11 . . . . simplify

  y = -1 . . . . . . . multiply by y/-11

Using the second equation, we can find x:

  2/x +1/-1 = 3

  2/x = 4 . . . . . . . add 1

  x = 1/2 . . . . . . . multiply by x/4

The solution is (x, y) = (1/2, -1).

_____

<em>Additional comment</em>

If you clear fractions by multiplying each equation by xy, the problem becomes one of solving simultaneous 2nd-degree equations. It is much easier to consider this a system of linear equations, where the variable is 1/x or 1/y. Solving for the values of those gives you the values of x and y.

A graph of the original equations gives you an extraneous solution of (x, y) = (0, 0) along with the real solution (x, y) = (0.5, -1).

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Answer:

<h2>43°</h2>

Step-by-step explanation:

In a cyclic quadrilateral, the sum of two opposite angles are equal.

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plugging the values:

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divide both sides of the equation by 4

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Hope this helps...

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Step-by-step explanation:

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1

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