Answer:
Step-by-step explanation:
The problem statement defines the variables and gives the relations ...
2b + f = 8 . . . . total cost on Monday
3b + f = 11 . . . . total cost on Tuesday
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Subtracting the first equation from the second, we get ...
(3b +f) -(2b +f) = 11 -8
b = 3 . . . . . simplify
Substituting this into the first equation, we can solve for f
2·3 +f = 8
f = 2 . . . . . . . subtract 6
Bagels cost $3 per dozen; the delivery fee is $2.
Choices A and B have typos in them, so its not clear what you're trying to say for those parts. However, the domain of 
is 
meaning that x can be 0 or larger. In other words, we can't have x be negative. Similarly, y is the same story because has the inverse 
, but only when , so therefore 
as well. In short you can say both x and y are nonnegative.
To summarize so far, the domain is and the range is
Since x = 0 and y = 0 are the smallest x and y values possible, this means (x,y) = (0,0) is the left-most point or where the graph starts. This is the origin. Choice C is a true statement.
Choice D on the other hand is <u>not</u> a true statement. Graph out and you'll see that a straight line does not form, but instead a nonlinear curve that grows forever. That growth gradually diminishes as x gets larger. Algebraically you can pick three points from the function and show that the slopes are different. Say the three points are P, Q and R. If you can show that slope of PQ does not equal slope of QR, then the function is not linear.
B. The total cost depends on the number of roses purchased.
Which of the sets of ordered pairs represents a function? A = {(1, −5), (8, −5), (8, 7), (2, 9)} B = {(7, −4), (7, −2), (6, −3),
jek_recluse [69]
Answer:
Neither A or B
Step-by-step explanation:
Hello There!
In order for a set of ordered pairs to represent a function none of the x values can repeat
In answer choice A the x value 7 repeats therefore the set of ordered pairs do not represent a function
In answer choice B the x value 7 repeats therefore the set of ordered pairs do not represent a function
so we can conclude that neither set of ordered pairs represent a function
