Given one to one f(6)=3, f'(6)=5, find tangent line to y=f⁻¹(x) at (3,6)
OK, we know
f⁻¹(3)=6
The inverse function is the reflection in y=x. So slopes, i.e. the derivative will be the reciprocal. We know the derivative of f at 6 is 5, so the derivative of f⁻¹ at y=6 is 1/5, which corresponds to x=3.
f⁻¹ ' (3) = 1/5
That slope through (3,6) is the tangent line we seek:
y - 6 = (1/5) (x-3)
That's the tangent line.
y = x/5 + 27/5
Answer:
1.05 * 4.6 is n
Step-by-step explanation:
9514 1404 393
Answer:
$6.55
Step-by-step explanation:
The cost will be multiplied by 1 +3% = 1.03 each year, so after 30 years, the cost will be ...
$2.70 × 1.03^30 ≈ $6.55
Answer:
c = 55 . . . . (no units for cost are given in your problem statement)
Step-by-step explanation:
"t is the number of tickets" and "Marci bought 20 tickets", so we conclude t=20. Putting that value into the equation and doing the arithmetic, we find ...
c = 2.75·20 = 55
_____
We don't know if this is pennies or pounds, dollars or rupees or pesos or euros. No monetary units are mentioned in the problem statement given here.
Answer:
you are a wonderful human being dont give me on whats here for you in this world
Step-by-step explanation:
