Answer:
Value is 15 and measure is 151
Given the coordinates of the three vertices of a triangle ABC,
the centroid coordinates are (x1+x2+x3)/3, (y1+y2+y3)/3
<span>so (-4+2+0)/3=-2/3, ]2+4+(-2)]/3=4/3
so the coordinates are (-2/3, 4/3)</span>
We need Pythagoras theorem here
a^2+b^2 = c^2
a, b = legs of a right-triangle
c = length of hypotenuse
Let S=shorter leg, in cm, then longer leg=S+2 cm
use Pythagoras theorem
S^2+(S+2)^2 = (10 cm)^2
expand (S+2)^2
S^2 + S^2+4S+4 = 100 cm^2 [collect terms and isolate]
2S^2+4S = 100-4 = 96 cm^2
simplify and form standard form of quadratic
S^2+2S-48=0
Solve by factoring
(S+8)(S-6) = 0 means (S+8)=0, S=-8
or (S-6)=0, S=6
Reject nengative root, so
Shorter leg = 6 cm
Longer leg = 6+2 cm = 8 cm
Hypotenuse (given) = 10 cm
Answer: 31.5 in.
Answer:
the answer is 13 cm
Step-by-step explanation:
Answer:
y = 4x - 19
Step-by-step explanation:
The line is parallel to the line whose equation is;
y = 4x + 1
Parallel lines have the same slope so the slope of our line is 4.
The line passes through point (5,1)
Slope = change in y ÷ change in x
Taking another point (x,y) on the line,
Slope = 
= 4
y - 1 = 4x - 20
y = 4x - 19
