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Serjik [45]
3 years ago
7

Simplify 78 - 74 A. 712 B. 74 C. 7-4 D. 72 su Thanks

Mathematics
1 answer:
boyakko [2]3 years ago
4 0

Hey!

Divide the exponents. 8/4=2

So your answer its D.

Hope this helps!

<h2><em>~~~PicklePoppers~~~</em></h2>
You might be interested in
Jake and Danny agree to share the cost of renting a house for $1100. If Jake agrees to pay $250 more than Danny, how much money
SVEN [57.7K]

Step-by-step explanation:

First divide 1100 by 2

550

Now that would be the amount the both of them would have to pay if they were splitting it equally. Since there not add 250 to 550.

250+550=800

Finally subtract 250 from 550

550-250=300

Jake has to pay $550

Danny has to pay $300

7 0
3 years ago
Matt and Mark went to El Rodeo to have some dinner. Matt ordered 3 tacos and 2 enchiladas, which cost him $4.93. Mark ordered 2
lord [1]

Answer:

The cost of one taco is $0.87 and the cost of one enchilada is $1.16

Step-by-step explanation:

Let the cost of tacos be X

and cost of enchiladas be y

So, by using given data, we have following equations

3X + 2Y = 4.93             (1)

2X + 4Y = 6.38             (2)

So, first multiply 1st equation by 2 and 2nd equation by 3, then subtracting 1st equation by 2nd.

= 2 × ( 3X + 2Y = 4.93)       (1)

= 3 × (2X + 4Y = 6.38)        (2)

= - (6X + 4Y = 9.86)              (1)

= 6X + 12y = 19.14            (2)

= 8Y = 9.28

Y = 9.28 ÷ 8 = 1.16

By putting the value of Y in equation 1, we get

3X + 2(1.16) = 4.93

3X + 2.32 = 4.93

X = 2.61 ÷ 3 = 0.87

Hence, the cost of one taco is $0.87 and the cost of one enchilada is $1.16.

8 0
3 years ago
Jackson was selling cups of lemonade for a school football fundraiser. On Saturday, he sold a total of 26 cups.
marin [14]

Answer:

how much did he sell them for

because what ever it it just do 26x__

7 0
2 years ago
Decrease <br>133 in the ratio 7:2​
love history [14]

Answer:

38

Step-by-step explanation

2/7× 133=38

6 0
3 years ago
"Solving Equations by Completing the Square: m^2+2m-48=-6
kvv77 [185]
m^2+2m-48=-6 \\ \\ m^2+2m-48+6=0\\ \\m^2+2m-42=0\\ \\a=1, \ b= 2, \ c= -42 \\ \\\Delta = b^{2}-4ac = 2^{2}-4*1*(-42)= 4+168 =172 \\\\\sqrt{\Delta }=\sqrt{172} =\sqrt{4*43}=2\sqrt{43}\\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-2-2\sqrt{43}}{2}=\frac{2(-1-\sqrt{43})}{2}= -1-\sqrt{43} \\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} = \frac{-2+2\sqrt{43}}{2}=\frac{ 2(-1+\sqrt{43})}{2}= -1+\sqrt{43}
5 0
3 years ago
Read 2 more answers
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