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Vinvika [58]
3 years ago
15

What does the word "eliminate" most likely mean, as it is used in this

Mathematics
1 answer:
stiks02 [169]3 years ago
5 0

Answer:

This is Exclude because they didn’t want them anymore or didn’t want to hire them or include them in a conversation.

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4.538461538 rounded to nearest 10th
Nutka1998 [239]
It would be 4.5
Hope this helps. 
7 0
3 years ago
Joan multiplied 9.1 by 0.001.   The product will be greater than which value?   A. 9.0   B. 0.90   C. 0.090   D. 0.0090
aivan3 [116]
I'm guessing 9.1 is a typo and it's suppose to be 9.0. In that case, the answer is D
7 0
3 years ago
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Please help me ASAP!
White raven [17]
Since lean beef has 2 legs and there is 18 legs in total, there are 9 lean beef cows.
20 - 9 = 11
There is 11 more ground beefs than lean beefs.
Hope this helps
3 0
3 years ago
Read 2 more answers
Suppose that the members of a student governance committee will be selected from the 40 members of the student senate. There are
Len [333]

Answer:

The total number of ways to form a student governance committee is 1,211,760.

Step-by-step explanation:

The students senate consists of a total of 40 students.

The students are either Sophomores or Juniors or Seniors.

The number of students in each of these categories are as follows:

Sophomores = 18

Juniors = 12

Seniors = 10

A governance committee have to be selected from the students senate.

The committee have to made up of 2 sophomores, 2 juniors and 3 seniors.

Combinations can be used to select 2 sophomores from 18, 2 juniors from 12 and 3 seniors from 10.

Combinations is a mathematical technique used to determine the number of ways to select <em>k</em> items from <em>n</em> distinct items.

The formula is:

{n\choose k}=\frac{n!}{k!(n-k)!}

(1)

Compute the number of ways to select 2 sophomores from 18 as follows:

{n\choose k}=\frac{n!}{k!(n-k)!}

{18\choose 2}=\frac{18!}{2!(18-2)!}=\frac{18\times 17\times 16!}{2\times 16!}=153

Thus, there are 153 ways to select 2 sophomores from 18.

(2)

Compute the number of ways to select 2 juniors from 12 as follows:

{n\choose k}=\frac{n!}{k!(n-k)!}

{12\choose 2}=\frac{12!}{2!(12-2)!}=\frac{12\times 11\times 10!}{2\times 10!}=66

Thus, there are 66 ways to select 2 juniors from 12.

(3)

Compute the number of ways to select 3 seniors from 10 as follows:

{n\choose k}=\frac{n!}{k!(n-k)!}

{10\choose 3}=\frac{10!}{3!(10-3)!}=\frac{10\times 9\times 8\times 7!}{2\times 3\times 7!}=120

Thus, there are 120 ways to select 3 seniors from 10.

The total number of ways to form a student governance committee that must have 2 sophomores, 2 juniors and 3 seniors is:

Total number of ways = {18\choose 2}\times {12\choose 2}\times {10\choose 3}

                                    =153\times 66\times 120\\=1211760

Thus, the total number of ways to form a student governance committee is 1,211,760.

7 0
3 years ago
What is the value of l-9+xl-24 when x=-5?
sergeinik [125]
-35.6666666666667
Is the answer I think
6 0
3 years ago
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