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Rasek [7]
3 years ago
13

A regular hexagon and a rectangle have the same perimeter, P. A side of the hexagon is 4 less than the length, l, of the rectang

le. The width of the rectangle, w, is 2 less than the length of the rectangle. What is the perimeter of the hexagon?
A rectangle with a length of l and width of w. P = 2 l + 2 w. A hexagon with side lengths of s. P = 6 s.
Mathematics
1 answer:
disa [49]3 years ago
3 0

The answer and explanation is given in the picture below

I hope it helps.

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\bf \begin{array}{|cc|ll} \cline{1-2} x&y\\ \cline{1-2} 40&32\\ 28&16\\ 16&12\\ \cline{1-2} \end{array}~\hfill \stackrel{\textit{average rate of change}}{slope} \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{40}~,~\stackrel{y_1}{32})\qquad (\stackrel{x_2}{28}~,~\stackrel{y_2}{16}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{16-32}{28-40}\implies \cfrac{-16}{-12}\implies \boxed{\cfrac{4}{3}} \\\\[-0.35em] ~\dotfill

\bf (\stackrel{x_1}{28}~,~\stackrel{y_1}{16})\qquad (\stackrel{x_2}{16}~,~\stackrel{y_2}{12}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{12-16}{16-28}\implies \cfrac{-4}{-12}\implies \boxed{\cfrac{1}{3}}

8 0
3 years ago
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lapo4ka [179]
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7 0
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Find the equation of a line that contains the points (−3,−1) and (−4,−7). Write the equation in slope-intercept form
ikadub [295]

Answer:

  y = -8x -25

Step-by-step explanation:

The 2-point form of the equation of a line is useful when you are given 2 points.

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7 0
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5 0
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