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Dmitrij [34]
4 years ago
5

HURRY!!!!!!!!! Given P(5,10,8) and Q(7,11,10), find the midpoint of the segment PQ.

Mathematics
1 answer:
rusak2 [61]4 years ago
4 0

Answer:

P_{m}=(6,10.5,9)

Step-by-step explanation:

The mid point can be found with the formula

P_{m}=(\frac{x_{1}+x_{2} }{2},\frac{y_{1} +y_{2} }{2} ,\frac{z_{1}+z_{2}  }{2} )

The given coordinates are P(5,10,8) and Q(7,11,10).

Replacing coordinates in the formula, we have

P_{m}=(\frac{5+7}{2},\frac{10+11 }{2} ,\frac{8+10}{2} )=(\frac{12}{2},\frac{21 }{2} ,\frac{18}{2} )\\P_{m}=(6,10.5,9)

Therefore, the mid point of the segment PQ is P_{m}=(6,10.5,9)

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The function is:

f ( x ) = x² - x - 72

This is a quatdratic function. So we can find the zeroes of the function with the formula:

x 1/2 = ( - b +/- √(b² - 4 ac) ) / ( 2a )

And we have: a = 1, b = - 1 and c = - 72

x 1/2 = ( 1 +/- √((-1)² - 4 · 1· ( - 72 )) ) / 2

x 1/2 = ( 1 +/- √( 1 + 288 ) ) / 2

x 1/2 = ( 1 +/- √289 ) / 2

x 1/2 = ( 1 +/- 17 ) / 2

x 1 = ( 1 - 17 ) 2 = - 16 / 2 = - 8

x 2 = ( 1 + 17 ) / 2 = 18 / 2 = 9

Answer: The zeroes are - 8 and 9.

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The number of failures of a testing instrument from contamination particles on the product is a Poisson random variable with a m
photoshop1234 [79]

Answer: 0.1353

Step-by-step explanation:

Given : The mean of failures =  0.025 per hour.

Then  for 8 hours , the mean of failures = \lambda=8\times0.25=2 per eight hours.

Let X be the number of failures.

The formula to calculate the Poisson distribution is given by :_

P(X=x)=\dfrac{e^{-\lambda}\lambda^x}{x!}

Now, the probability that the instrument does not fail in an 8-hour shift :-

P(X=0)=\dfrac{e^{-2}2^0}{0!}=0.1353352\approx0.1353

Hence, the the probability that the instrument does not fail in an 8-hour shift = 0.1353

7 0
3 years ago
Find the midpoint of points A(8,-7) and B(3,-1) graphically
sukhopar [10]

Answer: (5.5, -4)

Step-by-step explanation:

You can use the midpoint formula to find the midpoint of point A and point B.

M(\frac{x_{1}+x_{2} }{2}, \frac{y_{1} + y_{2} }{2})

x₁ = 8

x₂ = 3

y₁ = -7

y₂ = -1

M(\frac{x_{1}+x_{2} }{2}, \frac{y_{1} + y_{2} }{2})

M(\frac{8+3 }{2},  \frac{-7 +-1}{2} )

M(\frac{8+3 }{2},  \frac{-7 -1}{2} )

M(\frac{11 }{2},  \frac{-8}{2} )

M(5.5, -4 )

Midpoint = (5.5, -4)

Hope this helps!

3 0
3 years ago
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