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Damm [24]
2 years ago
8

Peter's Party Zone sells cups in packages of 666 and plates in packages of 888.

Mathematics
1 answer:
lilavasa [31]2 years ago
5 0

Answer:

the answer would be 24

Step-by-step explanation:

what you would need to do is find the LCM of 6 and 8

so the lcm of 6 and 8 =2 <em>times</em> 2<em> times</em> 2 <em>times </em>3= 24\

HOPE THIS HELPED<333

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Estimate by rounding each number to the nearest hundredth and then subtract 360.727 - 89.852
kykrilka [37]
Hi there!

The correct answer for you is 270.88.

To round to the hundreth's place (.0<u>1</u><u />), you need to take the number in the thousand's place (.00<u>1</u>), and determine if the number needs to go up or down.

If the number in the thousand's place is <u>greater</u> than 4, then the number goes up.

360.72<u>7</u> --> This means that the hundreth's number goes up to 3.

If the number in the thousand's place is <u>lesser</u> than 5, then that number stays the same.

89.85<u>2</u> --> This means that the hundreth's number stays the same.

After you round, then just subtract:

360.73 - 89.85 = 270.88.

I hope this helps!
Brady
<u />

7 0
3 years ago
What percentage of babies born in the United States are classified as having a low birthweight (&lt;2500g)? explain how you got
lawyer [7]

Answer:

2.28% of babies born in the United States having a low birth weight.

Step-by-step explanation:

<u>The complete question is</u>: In the United States, birth weights of newborn babies are approximately normally distributed with a mean of μ = 3,500 g and a standard deviation of σ = 500 g. What percent of babies born in the United States are classified as having a low birth weight (< 2,500 g)? Explain how you got your answer.

We are given that in the United States, birth weights of newborn babies are approximately normally distributed with a mean of μ = 3,500 g and a standard deviation of σ = 500 g.

Let X = <u><em>birth weights of newborn babies</em></u>

The z-score probability distribution for the normal distribution is given by;

                          Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean = 3,500 g

            \sigma = standard deviation = 500 g

So, X ~ N(\mu=3500, \sigma^{2} = 500)

Now, the percent of babies born in the United States having a low birth weight is given by = P(X < 2500 mg)

         

   P(X < 2500 mg) = P( \frac{X-\mu}{\sigma} < \frac{2500-3500}{500} ) = P(Z < -2) = 1 - P(Z \leq 2)

                                                                 = 1 - 0.97725 = 0.02275 or 2.28%

The above probability is calculated by looking at the value of x = 2 in the z table which has an area of 0.97725.

4 0
3 years ago
What is the missing reason in the proof?
spayn [35]
Perpendicular bisector theorem
5 0
3 years ago
Read 2 more answers
The Statue of Liberty is about 300 feet tall and about 30 feet wide. The town of Unionville is building a smaller model for thei
hichkok12 [17]
It’s dividing by a factor of 10. So 30 divided by 10=3. You then do the same thing for the height. 300 divided by 10=30. The answer is 30.
5 0
3 years ago
What is the value of a in the equation a = 2 + 3a + 10?
xxTIMURxx [149]

Answer:

a= -6

Step-by-step explanation:

Given

a=2+3a+10

In order to find the value of a, we have to isolate a on a single side of the equation

So,

subtracting 3a from both sides

a-3a = 2+10+3a-3a

=>a-3a=12

=> -2a = 12

Dividing both sides by -2

=> -2a/-2 = 12/-2

=> a = -6

The value of a in the given equation is -6 ..

3 0
2 years ago
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