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DENIUS [597]
3 years ago
12

Help me pleasee......

Mathematics
2 answers:
bagirrra123 [75]3 years ago
7 0
56.7 should be the right answer
Gnoma [55]3 years ago
7 0

Answer:

∠ETM is 56.7

Step-by-step explanation:

168.7 - 112

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17more than a number is 85​
Levart [38]

Answer:

Well a number is (x) {unknown}

Its 17 more

So x+17=85

Now solve

subtract 17 on both sides

x=68

So the number is 68

7 0
3 years ago
Read 2 more answers
PICTURE INCLUDED!! PLEASE HELP !! WHICH OF THE FOLLOWING EQUATIONS DESCRIBE THE LINE SHOWN BELOW (-1,6) (2,-6)
GalinKa [24]
(-1,6)(2,-6)
slope = (-6 - 6) / (2 - (-1) = -12 / 3 = - 4

y = mx + b
slope(m) = -4
(-1,6)...x = -1 and y = 6
sub and find b
6 = -4(-1) + b
6 = 4 + b
6 - 4 = b
2 = b

ur equation is : y = -4x + 2 <== this is one

(-1,6)
y - 6 = -4(x + 1) <== this is one


8 0
3 years ago
45% of what number is 144
meriva
45% - 144
100% - x

/cross multiply/

45x = 144·100
45x = 14400    |divide both sides by 45
x = 320

Answer: 45% of 320 is 144.
5 0
3 years ago
Read 2 more answers
A pencil holder shaped like a triangular prism is shown in the picture. The height of the pencil holder is 12 cm, and the volume
algol13

Answer:

18cm

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Suppose that 1 kg of Sodium-24 is reduced to 0.0156 kg in 90 hours. What is the half-life, in hours, of Sodium-24?​
N76 [4]

Answer:

14.99 hours

Step-by-step explanation:

The formula for half-life is given as,

R/R' = 2ᵃ/ᵇ...................... Equation 1

Where R= Original mass of sodium-24, R' = mass of Sodium-24 after disintegration, a = Total time taken for sodium-24 to disintegrate, b = half-life of sodiun-24.

Given: R = 1 kg, R' = 0.0156 kg, a = 90 hours

Substitute into equation 1 and solve for b

1/(0.0156) = 2⁹⁰/ᵇ

Taking the log of both side

log[1/(0.0156)] = log(2⁹⁰/ᵇ)

log[1/(0.0156)] = 90/b(log2)

90/b = log[1/(0.0156)]/log2

90/b = 6.0023

b = 90/6.0023

b =  14.99 hours

b = 14.99 hours.

Hence the half-life of Sodium-24 is 14.99 hours

7 0
3 years ago
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