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2 years ago

Use the parabola tool to graph the quadratic function f(x) = x2 – 12x + 27.

Mathematics

1 answer:

Dennis_Churaev [7]2 years ago

5 0

Answer:

Step-by-step explanation:

you would chose 7 because it has more and less value

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(0, -4), (-4, 6) what the equation y=mx+b<br>

valentinak56 [21]

Y=(2/5)x-4
Or
Y=0.4x-4

6 0

2 years ago

2. Which of the following statements is true?

Vesnalui [34]

The first and last choices are true.

4 0

3 years ago

Given the function g(x)=√x+4, which of the following values cannot be the domain of g?

Gennadij [26K]

Answer:

D. x = -5

Step-by-step explanation:

The square root function is only defined for non-negative arguments. For the function ...

$g(x)=\sqrt{x+4}$

this means we must have ...

x +4 ≥ 0

x ≥ -4 . . . . . . subtract 4 from both sides

All of the numbers on your answer choice list are more than -4 except -5.

x = -5 is not in the domain of g(x)

6 0

2 years ago

Let sin(45°)=0.7071.Enter the angle measure (μ), in degrees for cos(μ)=−0.7071.

Alenkasestr [34]

Given :

Let sin(45°)=0.7071.

To Find :

The angle measure (μ), in degrees for cos(μ)=−0.7071 and value equivalent to 360n + , where n is an integer .

Solution :

We know , value of sin x and cos x is same at x = 45° .

Now , cos (-x) = cos(90°+x)

Therefore , μ in given question is :

μ =90°+45°

μ=135°

So , for angle of type 360°n + :

μ = 360°n + 135° .

Hence , this is the required solution .

5 0

3 years ago

given the function f(x)=x^3 +x^2-2x+1 what is the resulting function f(x) is shifted to the left one unit

Nadya [2.5K]

Answer:

The resulting function is $f(x+1) = x^3 + 4x^2 + 3x + 1$

Step-by-step explanation:

Suppose we have a function f(x). If we want to shift the function 1 unit to the left, we find f(x+1).

In this question, we have:

$f(x) = x^3 + x^2 - 2x + 1$

Shifting 1 unit to the left:

$f(x+1) = (x+1)^3 + (x+1)^2 - 2(x+1) + 1$

$f(x+1) = (x^3 + 3x^2 + 3x + 1) + (x^2 + 2x + 1) - 2x - 2 + 1$

$f(x+1) = x^3 + (3+1)x^2 + (3+2-2)x + 1 + 1 - 2 + 1$

$f(x+1) = x^3 + 4x^2 + 3x + 1$

The resulting function is $f(x+1) = x^3 + 4x^2 + 3x + 1$

8 0

2 years ago