All categories

3 years ago

Write 8/5 in a mixed number

2 answers:

8 0

He improper fraction 8/5<span> can be changed to the </span>mixed number<span> 1 3/5 by dividing the numerator (8) by the denominator (5). This gives a quotient of 1 and a remainder of 3. The remainder is placed over the divisor (5).</span>

Licemer1 [7]3 years ago

3 0

The answer for that question is 1 3/5

You might be interested in

Lupita has five times as much money as David. Lupita also has $20 more than David. How much money does each person have?

zhannawk [14.2K]

20x5 is 100 for each

6 0

1 year ago

What is the equation of the graph below? A graph shows a parabola that opens up and crosses the x axis at negative two and negat

Anastaziya [24]

Answer:

$y=(x+3)^{2} -1$

Step-by-step explanation:

General equation of a parabola that opens up is $y=a(x-h)^{2} +k$ , a>0

So equation becomes $y=(x-h)^{2} +k$ which implies option A and option B can never be true for this parabola.

Also this parabola's vertex lies in 3rd quadrant where coordinates of both x and y will be negative.

So, the equation of parabola will be of the form $y=(x+h)^{2} - k$

Hence, option 4 that is $y=(x+3)^{2} -1$ is correct.

4 0

2 years ago

Read 2 more answers

The graphs of f(x) and g(x) are shown below:

rosijanka [135]

<h2>Answer:</h2>

Option: C is the correct answer.

C.) x = −3.8, 3

<h2>Step-by-step explanation:</h2>

The function f(x) is given by:

$f(x)=x^2-x-12$

and the function g(x) is given by:

$g(x)=-1.8x-0.6$

Now, we are asked to find the solution of the equation:

$f(x)=g(x)$

i.e. we have to find the value of x such that both the functions are equal i.e.

$x^2-x-12=-1.8x-0.6\\\\i.e.\\\\x^2-x+1.8x-12+0.6=0\\\\i.e.\\\\x^2+0.8x-11.4=0\\\\i.e.\\\\10x^2+8x-114=0\\\\i.e.\\\\5x^2+4x-57=0$

Now, on solving the equation using the quadratic formula i.e. the solution of the equation:

$ax^2+bx+c=0$

is given by:

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

Here we have:

$a=5,\ b=4\ and\ c=-57$

Hence, the solution is given by:

$x=\dfrac{-4\pm \sqrt{4^2-4\times 5\times (-57)}}{2\times 5}\\\\i.e.\\\\x=\dfrac{-4\pm \sqrt{16+1140}}{10}\\\\i.e.\\\\x=-3.8\ and\ x=3$

6 0

3 years ago

A truck can be rented from Company A form $130 a day plus $0.30 per mile. Company B charges $50 a day plus $0.80 per mile to r

navik [9.2K]

Answer:

160 miles

Step-by-step explanation:

Company A form $130 a day plus $0.30 per mile

Company A = 130 + 0.30x

Company B charges $50 a day plus $0.80 per mile

Company B = 50 + 0.80x

Where,

x = number of miles

Equate the cost of company A and company B

130 + 0.30x = 50 + 0.80x

Collect like terms

130 - 50 = 0.80x - 0.30x

80 = 0.50x

Divide both sides by 0.50x

x = 80 / 0.50

= 160

x = 160 miles

The number of miles in a day at which the rental costs for Company A and Company B are the same is 160 miles

4 0

2 years ago

I need helpppp, I need to turn this in before class is over

svetoff [14.1K]

Answer:

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers