Answer:
C
Step-by-step explanation:
In this technique, if we have to factorise an expression like ax2+bx+c, we need to think of 2 numbers such that:
N1⋅N2=a⋅c=1⋅−12=−12
AND
N1+N2=b=−1
After trying out a few numbers we get N1=3 and N2=−4
3⋅−4=−12, and 3+(−4)=−1
x2−x−12=x2−4x+3x−12
x(x−4)+3(x−4)=0
(x+3)(x−4)=0
Now we equate the factors to zero.
x+3=0,x=−3
x−4=0,x=4
Answer:
they r all the same shap but that is all I know
-2y + 6 < 10
Subtract 6 on both sides
-2y < 10
Divide by -2 on both sides
y > -5
Hope this helps! Just in case you don’t understand the final answer, when dividing or multiplying by a negative number you flip the sign!
Answer:
The correct answer is :
1. Line PQ (One line PQ).
Step-by-step explanation:
The first step to solve this question is to draw the plane A with the points P and Q lying on it.
We know that given two different points there is only one line that contains this two different points.
Let's analyze each option.
''2. Lines PQ and QP''
This option is wrong because there aren't two different lines. In fact it is only one line that can be named line PQ or line QP.
''3. The 2 lines PQ and QP plus another line that does not lie in plane A.''
This option is assuming that exist three lines that contain P and Q. This option is also wrong.
''1. Line PQ''
This option is correct. It will be clarify with the drawing I will attach.
''We can't name them all!''
This option is assuming that exist infinite lines that contain P and Q. This option is wrong.
In the drawing I call the line that contains P and Q as line L.
Given that P and Q lie in plane A necessarily the line L must lie on the plane A.
It's the first one you can just add or multiply the expressions to get the answer