Can anyone help me out??

Mathematics

1 answer:

Troyanec [42]3 years ago

7 0

9514 1404 393

Answer:

p(1) = 6

Step-by-step explanation:

The basic idea is to put 1 wherever you see x. That gives you ...

p(1) = 2·1² +3·1 +1

The powers of x are all 1 when x=1, so the value of p(1) is just the sum of the coefficients:

p(1) = 2 + 3 + 1

p(1) = 6

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What is the area of this triangle? (Image Attached)

Snezhnost [94]

$\bf \textit{Law of Cosines}\\ \quad \\
c^2 = {{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)\implies 
c = \sqrt{{{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)}\\\\
-----------------------------\\\\
\textit{so, let's find the missing side}
\\\\\\
c=\sqrt{2.7^2+3.4^2-2(2.7)(3.4)cos(40^o)}
\\\\\\
c=\sqrt{4.78542402433556327368}\implies c\approx 2.187561204706182220$

or we can round it, to say c = 2.19, so hmm that's the missing side
now, we use Heron's Formula, which uses all 3 sides only

$\bf \textit{Heron's Area Formula}\\\\
A=\sqrt{s(s-a)(s-b)(s-c)}\qquad 
\begin{cases}
a=2.7\\
b=3.4\\
c\approx 2.19\\\\
s=\cfrac{a+b+c}{2}
\end{cases}$

and that'd be the area of it

6 0

3 years ago

Read 2 more answers

Will give brainliest if done properly

k0ka [10]

Answer:

$\sf \boxed{ \sf y - 3 = \dfrac{3}{2} (x - 6)}$