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2 years ago

9

In which quadrant does the point (13 , 20) lie? A. Quadrant III B. Quadrant I C. Quadrant IV D. Quadrant II

1 answer:

ruslelena [56]2 years ago

5 0

Answer:

B.

Step-by-step explanation:

The first quadrant is the upper right-hand corner of the graph, the section where both x and y are positive. The second quadrant, in the upper left-hand corner, includes negative values of x and positive values of y. The third quadrant, the lower left-hand corner, includes negative values of both x and y.

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Whats the perfect square number 5,8,36,or 44

telo118 [61]

Answer:

36

Step-by-step explanation:

6*6=36

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3 years ago

PLS HELP ME Giving brainliest!! On Monday, 316 students went on a trip to the zoo. All 6 buses were filled and 4 students had to

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Answer:

xx = (316 - 4) ÷ 6

xx = 52 students per bus

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3 years ago

PLEASE PLEASE PLEASE HELP ME!

Ghella [55]

Answer:

V of the solid = 40 in³

Step-by-step explanation:

volume of the first rectangular (on left)

l*w*h = 2*4*2=16 in³

volume of the rectangular (on the right)

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7 0

4 years ago

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Solve the system of equations by finding the reduced row echelon form of the augmented matrix. Write the solutions for x and y i

Gwar [14]

Answer:

The solutions for the given system of equations are:

$\left \{ {{x=-5} \atop {y=12-4z}} \right.$

Step-by-step explanation:

Given the equation system:

$\left \{ {{3x+y+4z=-3} \atop {-x+y+4z=17}} \right.$

We obtain the following matrix:

$\left[\begin{array}{cccc}3&1&4&-3\\-1&1&4&17\end{array}\right]$

<u>Step 1:</u> Multiply the fisrt row by 1/3.

$\left[\begin{array}{cccc}1&\frac{1}{3} &\frac{4}{3}&-1\\-1&1&4&17\end{array}\right]$

<u>Step 2:</u> Sum the first row and the second row.

$\left[\begin{array}{cccc}1&\frac{1}{3} &\frac{4}{3}&-1\\0&\frac{4}{3} &\frac{16}{3}&16\end{array}\right]$

<u>Step 3:</u> Multiply the second row by 3/4.

$\left[\begin{array}{cccc}1&\frac{1}{3} &\frac{4}{3}&-1\\0&1 &4&12\end{array}\right]$

<u>Step 4:</u> Multiply the second row by -1/3 and sum the the first row.

$\left[\begin{array}{cccc}1&0 &0&-5\\0&1 &4&12\end{array}\right]$

The result of the reduced matrix is:

$\left \{ {{x=-5} \atop {y+4z=12}} \right.$

This is equal to:

$\left \{ {{x=-5} \atop {y=12-4z}} \right.$

These are the solutions for the system of equations in terms of z, where z can be any number.

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3 years ago

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nignag [31]

C 39.99 adding it all together

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3 years ago

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