Correct, you're looking for an outer loop that loops from 0 to 15, and an inner loop from 0 to 50.
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The correct answer is B. Prioritized view
Explanation:
The word "priority" is used to describe events, places, people, etc. that are considered of great importance. This means a task that is considered a priority is more important than regular tasks. In this way, in management software such as Outlook that allows users to monitor and manage tasks or things to do, users can organize tasks based on importance by clicking options such as "prioritized" or "prioritized view" that will display task from the most important to the least important. Thus, the option that organizes tasks based on importance is the prioritized view.
Answer:
import java.util.Scanner;
public class FindMatchValue {
public static void main (String [] args) {
final int NUM_VALS = 4;
int[] userValues = new int[NUM_VALS];
int i = 0;
int matchValue = 0;
int numMatches = -99; // Assign numMatches with 0 before your for loop
userValues[0] = 2;
userValues[1] = 2;
userValues[2] = 1;
userValues[3] = 2;
matchValue = 2;
numMatches=0;
for(i=0;i<NUM_VALS;i++)
{
if(userValues[i]==matchValue)//cheking if the array element is equal to match value.
{
numMatches++;
}
}
System.out.println(numMatches);//printing the matchvalue.
}
}
Output:-
3
Explanation:
First I have set the value numMatches to 0 before the loop.Then I have user the for loop to iterate over the array.In the for loop I am checking that the array element is equal to the matchValue or not if it is equal then increasing the numMatches by 1.Then at last print the value of numMatches.
