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Rudiy27
2 years ago
12

Construct a 60angle NEEDED ASAP LIKE IN 5 MINUTES OR LESS

Mathematics
1 answer:
NikAS [45]2 years ago
5 0

Answer:

but how there is nothing i dk plz can you explain me what the question actually is?

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The circumference Is

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нσρє ι ¢συℓ∂ нєℓρ уσυ

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an anchor line for a tower needs to be replaced. the tower is 96ft tall. the anchor line is 105ft long. how far from the tower c
Fynjy0 [20]

Answer:

Let x be how far from the tower can it be placed

by Pythagorus theorem

x^2  + 96^2   = 105^2

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3 years ago
4. Which relation is also a function?
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Write the point-slope form of the equation for a line that passes through (–1, 4) with a slope of 2.
kondaur [170]

Point slope is a really easy form for linear equations. It lets you plug in the numbers from a cordinate that the line passes through on the graph and the slope directly. Here is the point slope equation:

y(2) - y(1) = m(x(2) - x(1)

(The (2) and (1) next to the x's and y's are suposed to be underneath them. There is also supposed to be an extra parentheses at the end.)

You would replace y(1) with the y value, x(1) with the x value, and m with the slope. For example, if you have a line that crosses through the point (6, 10) with a slope of 3, this is how you would write the equation of the line in point slope form:

y - 10 = 3(x - 6)

Now, for this problem, we have the point (1, 4) with a slope of 2. This is the point slope form for the given point and slope:

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The values of y1 and x1 are the values we plugged into this equation, 4 and 1.

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3 years ago
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(a) By inspection, find a particular solution of y'' + 2y = 14. yp(x) = (b) By inspection, find a particular solution of y'' + 2
SOVA2 [1]

Answer:

(a) The particular solution, y_p is 7

(b) y_p is -4x

(c) y_p is -4x + 7

(d) y_p is 8x + (7/2)

Step-by-step explanation:

To find a particular solution to a differential equation by inspection - is to assume a trial function that looks like the nonhomogeneous part of the differential equation.

(a) Given y'' + 2y = 14.

Because the nonhomogeneus part of the differential equation, 14 is a constant, our trial function will be a constant too.

Let A be our trial function:

We need our trial differential equation y''_p + 2y_p = 14

Now, we differentiate y_p = A twice, to obtain y'_p and y''_p that will be substituted into the differential equation.

y'_p = 0

y''_p = 0

Substitution into the trial differential equation, we have.

0 + 2A = 14

A = 6/2 = 7

Therefore, the particular solution, y_p = A is 7

(b) y'' + 2y = −8x

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = -8x

2Ax + 2B = -8x

By inspection,

2B = 0 => B = 0

2A = -8 => A = -8/2 = -4

The particular solution y_p = Ax + B

is -4x

(c) y'' + 2y = −8x + 14

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = -8x + 14

2Ax + 2B = -8x + 14

By inspection,

2B = 14 => B = 14/2 = 7

2A = -8 => A = -8/2 = -4

The particular solution y_p = Ax + B

is -4x + 7

(d) Find a particular solution of y'' + 2y = 16x + 7

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = 16x + 7

2Ax + 2B = 16x + 7

By inspection,

2B = 7 => B = 7/2

2A = 16 => A = 16/2 = 8

The particular solution y_p = Ax + B

is 8x + (7/2)

8 0
3 years ago
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