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2 years ago

HELP PLEASE ANYONE

Mathematics

1 answer:

defon2 years ago

5 0

Answer:

Step-by-step explanation:

joshua times 3 is basically derrick's amount

so 3j = d

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What are the side lengths of a rectangle if the area is 40 sq. Ft and the perimeter is 28 ft

VMariaS [17]

40 can be gotten by multiplying 10 & 4

28 can be found by adding 10 + 10 + 4 + 4

so the side lengths are 4 & 10

8 0

3 years ago

The total cost in dollars for Larry to have his birthday party at a local

luda_lava [24]

Answer:

$0 \leq p < 6$

Step-by-step explanation:

Given

$t = 6.95p + 29.95$

$Amount = 70$

Required

Determine the domain

First, we need to solve for p

Substitute 70 for t in $t = 6.95p + 29.95$

$70 = 6.95p + 29.95$

Collect Like Terms

$6.95p = 70 - 29.95$

$6.95p = 40.05$

Solve for p

$p = 40.05/6.95$

$p = 5.76$

This implies that Larry can not invite up to 6 people.

Hence, the domain can be represented as: $0 \leq p < 6$

7 0

3 years ago

To save money, a local charity organization wants to target its mailing requests for donations to individuals who are most suppo

mars1129 [50]

Answer:

The 80% confidence interval for difference between two means is (0.85, 1.55).

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for difference between two means is:

$CI=(\bar x_{1}-\bar x_{2})\pm t_{\alpha/2,(n_{1}+n_{2}-2)}\times SE_{\bar x_{1}-\bar x_{2}}$

Given:

$\bar x_{1}=M_{1}=6.1\\\bar x_{2}=M_{2}=4.9\\SE_{\bar x_{1}-\bar x_{2}}=0.25$

Confidence level = 80%

$t_{\alpha/2, (n_{1}+n_{2}-2)}=t_{0.20/2, (5+5-2)}=t_{0.10,8}=1.397$

*Use a <em>t</em>-table for the critical value.

Compute the 80% confidence interval for difference between two means as follows:

$CI=(6.1-4.9)\pm 1.397\times 0.25\\=1.2\pm 0.34925\\=(0.85075, 1.54925)\\\approx(0.85, 1.55)$

Thus, the 80% confidence interval for difference between two means is (0.85, 1.55).

3 0

3 years ago

Reduce this algebraic fraction. y^3 -3y^2+y-3 / y^2-9

blondinia [14]

Answer:

y³ - 3y² + 1/y+3

Step-by-step explanation:

y² - 9 = (y - 3) ( y + 3)

y-3/(y-3)(y+3) = 1/y+3

6 0

3 years ago

Read 2 more answers

2( 10 - a^2 ) + 7a If ( a = 4 )Evaluate each expression

Lostsunrise [7]

Solution:

Given:

$2(10-a^2)+7a$

when a = 4, substitute for a in the expression;

$\begin{gathered} 2(10-a^2)+7a=2(10-4^2)+7(4) \\ =2(10-16)+28 \\ =2(-6)+28 \\ =-12+28 \\ =16 \end{gathered}$

Therefore, if (a = 4), then

$2(10-a^2)+7a=16$

Hence, the answer is 16.

6 0

1 year ago