Answer:
maximum value of y = 3
Step-by-step explanation:
line Starts at -4 , 0 & turns at - 1 , 3
Slope = (3 - 0)/(-1 -(-4)) = 3/3 = 1
y = x + c
=> 0 = - 4 + c => c = 4
=> y = x + 4
line after turning crosses the y-axis at (0, 2) and the x-axis at (2, 0)
slope of this line : (0-2)/(2-0) = -1
y = - x + c
2 = 0 + c => c = 2
=> y = - x + 2
=> y = 2 - x
Values Drawn
x y
-4 0
-3 1
-2 2
-1 3
0 2
1 1
2 0
Answer:
11x + 4d
Step-by-step explanation:
8x + 9d + 3x -5d
To simplify this we have to group them by their like terms i.e.
= 8x + 3x + 9d - 5d
= 11x + 4d
Mark brainliest
<h3>
Answer: Choice B</h3>
Explanation:
Cosine is positive in quadrants I and IV, but quadrant IV isn't shaded in so we can rule out choice A.
Sine is positive in quadrants I and II. So far it looks like choice B could work. In fact, it's the answer because sin(pi/6) = 1/2 and sin(5pi/6) = 1/2. So if 0 ≤ sin(x) < 1/2, then we'd shade the region between theta = 0 and theta = pi/6; as well as the region from theta = 5pi/6 to theta = pi.
Choice C is ruled out because tangent is positive in quadrants I and III, but quadrant III isn't shaded.
Choice D is ruled out for similar reasoning as choice A. Recall that 
FG goes through the center of the circle, so FG is diameter.

EH=r=3
Answer: EH=3
Answer: The given logical equivalence is proved below.
Step-by-step explanation: We are given to use truth tables to show the following logical equivalence :
P ⇔ Q ≡ (∼P ∨ Q)∧(∼Q ∨ P)
We know that
two compound propositions are said to be logically equivalent if they have same corresponding truth values in the truth table.
The truth table is as follows :
P Q ∼P ∼Q P⇔ Q ∼P ∨ Q ∼Q ∨ P (∼P ∨ Q)∧(∼Q ∨ P)
T T F F T T T T
T F F T F F T F
F T T F F T F F
F F T T T T T T
Since the corresponding truth vales for P ⇔ Q and (∼P ∨ Q)∧(∼Q ∨ P) are same, so the given propositions are logically equivalent.
Thus, P ⇔ Q ≡ (∼P ∨ Q)∧(∼Q ∨ P).