The property used to rewrite the given expression is product property.
Answer: Option A
<u>Step-by-step explanation:</u>
Given equation:

The sum of the two logarithms of two quantities (on the same basis) corresponds to the logarithm of their product on the same basis. The product log is equal to the log’s sum of the factors.

There are several rules that you can use to solve logarithmic equations. One of these guidelines is the logarithmic products rule that you can use to differentiate complex protocols in different ways. Different values that can be valuable are the quota principle and the logarithm rule. The logarithmic products rule is essential and is regularly used in analysis to control logs and simplify baseline conditions.
Answer:
1oz
Step-by-step explanation:
5% as a decimal is .05
.05 x 20= 1
Im a keep editing since this is timed.
#1 x-8a/6=3a-2x
Multiply each term by 6 to remove fraction .
6(x-8a/6)= 3a(6)-2x(6)
X-8a=18a-12x
Add 12x both sides
X+12x-8a=18a-12x+12x
13x-8a= 18a
Add8a both sides
13x-8a+8a=18a+8a
13x=26a
Divide each side by 13
13x/13=26a/13
X= 26a/13
Reduce and cancel common factor .
X= 13(2a)/13(1)
X=2a/1
X=2a
Problem #2
3x-2a=7a find a
Subtract 3x both sides
3x-3x-2a=7a-3x
-2a=7a-3x
Subtract 7a both sides
-2a-7a=7a-7a-3x
5a=-3x
Divide both sides by 5
5a/5=-3x/5
A= -0.6 or -3/5
Problem#3
3(bx-2ab)=b(x-7a)+3ab
Distributed property
3(bx)+3(-2ab)=b(x)+b(-7a)+3ab
Simplify
3bx-6ab=bx-7ab+3ab
Add -7a plus 3ab on right side
3bx-6ab= bx-4ab
Subtract bx both sides
3bx-bx-6ab= bx -bx -4ab
Simplify
2bx-6ab= -4ab
Add 6ab both sides
2bx-6ab+6ab=6ab-4ab
2bx=2ab
Divide 2b both sides
X= 2ab/2b
Cancel 2 common
X= ab/b
X=a
A bacteria culture starts with 500 bacteria and doubles in size every half hour.1
(a) How many bacteria are there after 3 hours?
We are told “. . . doubles in size every half hour.” Let’s make a table of the time and population:
t 0 0.5 1.0 1.5 2.0 2.5 3.0
bacteria 500 1000 2000 4000 8000 16000 32000
Thus, after three hours, the population of bacteria is 32,000.
(b) How many bacteria are there after t hours?
In t hours, there are 2t doubling periods. (For example, after 4 hours, the population has doubled 8
times.) The initial value is 500, so the population P at time t is given by
P(t) = 500 · 2
2t